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anonymous
 5 years ago
\[\int\limits_{}^{} (6x11 / x+2) dx\]
anonymous
 5 years ago
\[\int\limits_{}^{} (6x11 / x+2) dx\]

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0nice job with the equation writing skill...kudos ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0frac{top}{bottom} makes a clean fraction

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You need to substitute x for x=u+2 and then solve (dx=du since d/dy of +2 is zero).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Err... that's not d/dy of +2 but the derivative of +2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{top}{australia}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int \frac{6x11}{x+2}dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks for the lesson in writing equations >:(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you get what I wrote msunprecedented?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol.... I was impressed by your talent ...still am :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0do you want the integral of 3 seperate terms; or is what I posted a correct interpretation of it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no its correct \[\int\limits_{}^{} \frac {6x11} {x+2} dx\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0... factoring might be possible but we would have to find out what value had been canceled before hand.... and then do partial decomposition as a possibility

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Actually, this is really simple if you view the fraction like this: \[6x/(x+2)  (11/x+2)\] Now that it's in this form, you split the integral into two : \[\int\limits_{?}^{?}6x/(x+2)dx  \int\limits_{?}^{?}11/(6x+2)dx\] This should be easier to integrate... let me know if you need more help

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the left is easy now :) the right still has a straggler.... that "x" up top can get bothersome

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and by left I mean right ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0would the uv substitution work well there?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0uv substitution wouldn't work because I don't think you could factor x+2. (I can't see a way to factor anyway)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.06x goes to zero pretty quick like; but I get ln(x+2) and get lost on integrateing that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hmm.. I think integration by substitution works here. If you let u=x+2, you can get the right equal to:\[\int\limits_{?}^{?} (6u12)/u *du\] Then you split the fraction one more time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I mean the left when I say the "right" above

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol..... stage left ...STAGE left!! :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yikes! I'm soo confused! Usub here? Integration by parts there? :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0msunprecedented, have you learnt how to do integration by substitution yet?
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