what value would you add to each side to complete square
x^2+18x=-8

- anonymous

what value would you add to each side to complete square
x^2+18x=-8

- katieb

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- amistre64

what value do you think we should add?

- anonymous

I am not sure 9

- anonymous

x^2+18x = x^2 + 2*9*x +0
here's the formula: a^2 + 2ab + b^2 = (a+b)^2
so, you can see a=x, b=9. you are missing b^2, to complete square you'll need b^2, which is 9^2=81
so add 81 to each side.

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## More answers

- anonymous

Is That it

- anonymous

try it, then you tell me the result.

- amistre64

9 is a good number to use, but it is naked the way it is; square it and were good :)

- anonymous

I am really confused should I square the complete equation?

- anonymous

you can't square the whole equation. you should end up with something like this
(x+a)^2+b=0
a and be can be positive or negative.

- anonymous

except for some cases where you can just put them together nicely, of course.

- anonymous

i had a similar problem and don't understand how to do it and how they came up with the answer it was x^2+16x=-7 the answer was 64

- anonymous

try to put the left side into this form a^2 + 2ab + b^2. add something to make b^2, remember, you add something, you have to subtract it

- anonymous

a=1 b=18 c=-8

- anonymous

I know that I am having problems solving this because I can't find an example to use

- amistre64

b^2 = (2ab/2a) *b

- anonymous

ok, I'll do you this one example.
x^2+16x=-7
x^2+16x+7=0
x^2+2*x*8+7=0
compare this to
a^2 + 2*a*b + b^2=(a+b)^2
you can see clearly that
a=x
b=8
so if b=8, b^2=64, you need to add 64, but you add 64, you need to subtract 64
then equation becomes
x^2 + 2*x*8 + 64 - 64 + 7=0
(a+8)^2 + (-64+7) = 0
(a+8)^2 - 57 = 0
there's the answer

- amistre64

18/2(1) = 9*9 = 81

- anonymous

(a+9)^2-73=0
So I would add 81 to both sides

- anonymous

??? I dont get it.

- anonymous

x^2+18x=-8
x^2+2*x*9+81-81+8=0
(a+9)^2+(-81+8)=0
(a+9)^2-73=0
I would add 81 to both sides

- anonymous

exactly. that's right

- anonymous

Thank you now I have an example to go by

- anonymous

anytime

- anonymous

5x^2-3=0 no solution is that correct?

- anonymous

thank you got to go let me know if that is right

- anonymous

you mean to complete square, no, but there are solutions, add 3 to both sides, then divide both sides by 5, you'll get x^2=3/5=(sqrt(3/5))^2=(-sqrt(3/5))^2
so x=sqrt(3/5) or x=-sqrt(3/5)

- anonymous

thanks i figured it out square root property

- anonymous

ah that's good, good luck with ur maths

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