Find the indefinite integral. (e^x - e^-x) / (e^x - e^-x)^5/2

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Find the indefinite integral. (e^x - e^-x) / (e^x - e^-x)^5/2

Mathematics
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beckm, when you integrate this, you're going to end up with something that uses the hypergeometric function. Have you heard of that?
no i have not
we have been using integration using substitution,

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What level mathematics are you taking?
Business Calculus
Yeah, you could consider setting \[e^x=\cosh u \]to end up with an integral form of\[\frac{1}{2^{3/2}}cosech^{3/2} u \]
But again, the hypergeometric function will be coming...
yeah i dont think we are learning that b/c our school yr is over in two weeks, and we are only learning integration using substituiton
Yeah...sorry :(

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