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anonymous

  • 5 years ago

Find the indefinite integral. (e^x - e^-x) / (e^x - e^-x)^5/2

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  1. anonymous
    • 5 years ago
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    beckm, when you integrate this, you're going to end up with something that uses the hypergeometric function. Have you heard of that?

  2. anonymous
    • 5 years ago
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    no i have not

  3. anonymous
    • 5 years ago
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    we have been using integration using substitution,

  4. anonymous
    • 5 years ago
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    What level mathematics are you taking?

  5. anonymous
    • 5 years ago
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    Business Calculus

  6. anonymous
    • 5 years ago
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    Yeah, you could consider setting \[e^x=\cosh u \]to end up with an integral form of\[\frac{1}{2^{3/2}}cosech^{3/2} u \]

  7. anonymous
    • 5 years ago
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    But again, the hypergeometric function will be coming...

  8. anonymous
    • 5 years ago
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    yeah i dont think we are learning that b/c our school yr is over in two weeks, and we are only learning integration using substituiton

  9. anonymous
    • 5 years ago
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    Yeah...sorry :(

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