anonymous
  • anonymous
find a radical equation of the form sqrt(ax+b)=x+c so that one solution is extraneous
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
okay. give an example of square root of a number.
anonymous
  • anonymous
4
anonymous
  • anonymous
okay so 4 is the square root of 16. so ax+b =16 and x+c = 4.

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anonymous
  • anonymous
say x is 3, then c is 1. and 3a+b is 16. lets say a is 4, then b is also 4.
anonymous
  • anonymous
so your equation could be sqrt(4x+4)=x+1
anonymous
  • anonymous
to find x, square both sides. and post what you got.
anonymous
  • anonymous
-x^2+4x+3=0
anonymous
  • anonymous
x=-1,-3
anonymous
  • anonymous
wait. what is (x+1)^2?
anonymous
  • anonymous
x^2+1
anonymous
  • anonymous
(a+b)^2 is a^2+b^2? are you sure about that?
anonymous
  • anonymous
its 4x+4=x^2+1^2
anonymous
  • anonymous
do you know the formula for \[(a+b)^{2} \]
anonymous
  • anonymous
okay, if you don't know the formula, you can tell me. I will explain.
anonymous
  • anonymous
wait i no this its 4x+4=x^2+2x+1
anonymous
  • anonymous
yes! solve that expression then.
anonymous
  • anonymous
(x=-1,3)
anonymous
  • anonymous
y, plug in x = 3 and x = -1 in your original expression, sqrt(4x+4)=x+1
anonymous
  • anonymous
oh wait. this is a bad example.
anonymous
  • anonymous
well, anyway, you get the idea. you have to follow the procedure I outlines, such that the original expression is solve by one value of x and the square expression is solved by 2 values of x, giving you one spurious value of x.

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