find a radical equation of the form sqrt(ax+b)=x+c so that one solution is extraneous

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find a radical equation of the form sqrt(ax+b)=x+c so that one solution is extraneous

Mathematics
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okay. give an example of square root of a number.
4
okay so 4 is the square root of 16. so ax+b =16 and x+c = 4.

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say x is 3, then c is 1. and 3a+b is 16. lets say a is 4, then b is also 4.
so your equation could be sqrt(4x+4)=x+1
to find x, square both sides. and post what you got.
-x^2+4x+3=0
x=-1,-3
wait. what is (x+1)^2?
x^2+1
(a+b)^2 is a^2+b^2? are you sure about that?
its 4x+4=x^2+1^2
do you know the formula for \[(a+b)^{2} \]
okay, if you don't know the formula, you can tell me. I will explain.
wait i no this its 4x+4=x^2+2x+1
yes! solve that expression then.
(x=-1,3)
y, plug in x = 3 and x = -1 in your original expression, sqrt(4x+4)=x+1
oh wait. this is a bad example.
well, anyway, you get the idea. you have to follow the procedure I outlines, such that the original expression is solve by one value of x and the square expression is solved by 2 values of x, giving you one spurious value of x.

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