anonymous
  • anonymous
what is the square root of 20x over X^3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\sqrt{(\frac{20x}{x^3})}\] This?
anonymous
  • anonymous
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anonymous
  • anonymous
Well, work with the inside of the square root first. How can you simplify \(\frac{20x}{x^3}\)

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anonymous
  • anonymous
you square out the 20 and get 2 square root 5
anonymous
  • anonymous
or \[2\sqrt{5}\]
anonymous
  • anonymous
I said to ignore the square root first. Just deal with inside the square root for a second.
anonymous
  • anonymous
\[\frac{20x}{x^3}\] Can be simplified to what?
anonymous
  • anonymous
you would multiply the numerator by \[ \times ^{3}\] and get \[20x ^{4}\]
anonymous
  • anonymous
No. \[\frac{20x}{x^3} = \frac{20*x}{x*x*x}\] We can cancel one x from top and bottom. \[=\frac{20}{x^2}\]
anonymous
  • anonymous
ohhhh and then I would get \[\sqrt{20} \over \sqrt{x ^{?}}\]
anonymous
  • anonymous
Yep
anonymous
  • anonymous
then get \[2\sqrt{5} \over x ^{2}\]
anonymous
  • anonymous
wait
anonymous
  • anonymous
its \[2\sqrt{5} \over \sqrt{x ^{2}}\]
anonymous
  • anonymous
then get \[2x ^{2} \sqrt{5} \]
anonymous
  • anonymous
please tell me if that is right!
anonymous
  • anonymous
No. \(\sqrt{x^2} = |x|\)
anonymous
  • anonymous
So you have \[\frac{2\sqrt{5}}{\sqrt{x^2}} = \frac{2\sqrt{5}}{|x|} \]
anonymous
  • anonymous
I think you should review fractions because you keep moving the things in the denominator up to the numerator.
anonymous
  • anonymous
You can't really do that.
anonymous
  • anonymous
\[a*b \ne \frac{a}{b} \] Unless a=1 and b=1
anonymous
  • anonymous
my teacher taught us that way. She said that youcan not have a square root in the demoninator
anonymous
  • anonymous
No, you can. Often people prefer to have only square roots in the numerator, but in that case you must multiply the top and bottom by an extra factor of the square root. \[\frac{a}{\sqrt{b}} \] \[= \frac{a}{\sqrt{b}} *1 \] \[= \frac{a}{\sqrt{b}} *\frac{\sqrt{b}}{\sqrt{b}} \] \[= \frac{a\sqrt{b}}{\sqrt{b^2}} \] \[= \frac{a\sqrt{b}}{b}\]
anonymous
  • anonymous
yea that looks like the way she said it
anonymous
  • anonymous
Does that make sense? You cannot just move the square root in the denominator up to the numerator. Otherwise you get bad values. \[\frac{a}{\sqrt{b}} = a\sqrt{b} \implies \frac{1}{\sqrt{b}} = \sqrt{b} \implies 1 = \sqrt{b^2} \implies b = 1\] So the only thing you can bring directly from the numerator to the denominator is a 1.
anonymous
  • anonymous
Or the denominator to the numerator.
anonymous
  • anonymous
ok
anonymous
  • anonymous
Are youa teacher?
anonymous
  • anonymous
I'm not a teacher.. Just a person who's done a lot of math and tutor people. Review your simplification rules for fractions: http://www.khanacademy.org/video/simplifying-rational-expressions-1?playlist=Algebra%20I%20Worked%20Examples
anonymous
  • anonymous
THANK YOU GOD BLESS YOU!!!! GOODNIGHT

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