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anonymous

  • 5 years ago

what is the square root of 20x over X^3

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  1. anonymous
    • 5 years ago
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    \[\sqrt{(\frac{20x}{x^3})}\] This?

  2. anonymous
    • 5 years ago
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    YEEEESSSSSSSSSSSSSSSSSSSSSS

  3. anonymous
    • 5 years ago
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    Well, work with the inside of the square root first. How can you simplify \(\frac{20x}{x^3}\)

  4. anonymous
    • 5 years ago
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    you square out the 20 and get 2 square root 5

  5. anonymous
    • 5 years ago
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    or \[2\sqrt{5}\]

  6. anonymous
    • 5 years ago
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    I said to ignore the square root first. Just deal with inside the square root for a second.

  7. anonymous
    • 5 years ago
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    \[\frac{20x}{x^3}\] Can be simplified to what?

  8. anonymous
    • 5 years ago
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    you would multiply the numerator by \[ \times ^{3}\] and get \[20x ^{4}\]

  9. anonymous
    • 5 years ago
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    No. \[\frac{20x}{x^3} = \frac{20*x}{x*x*x}\] We can cancel one x from top and bottom. \[=\frac{20}{x^2}\]

  10. anonymous
    • 5 years ago
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    ohhhh and then I would get \[\sqrt{20} \over \sqrt{x ^{?}}\]

  11. anonymous
    • 5 years ago
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    Yep

  12. anonymous
    • 5 years ago
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    then get \[2\sqrt{5} \over x ^{2}\]

  13. anonymous
    • 5 years ago
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    wait

  14. anonymous
    • 5 years ago
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    its \[2\sqrt{5} \over \sqrt{x ^{2}}\]

  15. anonymous
    • 5 years ago
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    then get \[2x ^{2} \sqrt{5} \]

  16. anonymous
    • 5 years ago
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    please tell me if that is right!

  17. anonymous
    • 5 years ago
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    No. \(\sqrt{x^2} = |x|\)

  18. anonymous
    • 5 years ago
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    So you have \[\frac{2\sqrt{5}}{\sqrt{x^2}} = \frac{2\sqrt{5}}{|x|} \]

  19. anonymous
    • 5 years ago
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    I think you should review fractions because you keep moving the things in the denominator up to the numerator.

  20. anonymous
    • 5 years ago
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    You can't really do that.

  21. anonymous
    • 5 years ago
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    \[a*b \ne \frac{a}{b} \] Unless a=1 and b=1

  22. anonymous
    • 5 years ago
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    my teacher taught us that way. She said that youcan not have a square root in the demoninator

  23. anonymous
    • 5 years ago
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    No, you can. Often people prefer to have only square roots in the numerator, but in that case you must multiply the top and bottom by an extra factor of the square root. \[\frac{a}{\sqrt{b}} \] \[= \frac{a}{\sqrt{b}} *1 \] \[= \frac{a}{\sqrt{b}} *\frac{\sqrt{b}}{\sqrt{b}} \] \[= \frac{a\sqrt{b}}{\sqrt{b^2}} \] \[= \frac{a\sqrt{b}}{b}\]

  24. anonymous
    • 5 years ago
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    yea that looks like the way she said it

  25. anonymous
    • 5 years ago
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    Does that make sense? You cannot just move the square root in the denominator up to the numerator. Otherwise you get bad values. \[\frac{a}{\sqrt{b}} = a\sqrt{b} \implies \frac{1}{\sqrt{b}} = \sqrt{b} \implies 1 = \sqrt{b^2} \implies b = 1\] So the only thing you can bring directly from the numerator to the denominator is a 1.

  26. anonymous
    • 5 years ago
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    Or the denominator to the numerator.

  27. anonymous
    • 5 years ago
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    ok

  28. anonymous
    • 5 years ago
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    Are youa teacher?

  29. anonymous
    • 5 years ago
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    I'm not a teacher.. Just a person who's done a lot of math and tutor people. Review your simplification rules for fractions: http://www.khanacademy.org/video/simplifying-rational-expressions-1?playlist=Algebra%20I%20Worked%20Examples

  30. anonymous
    • 5 years ago
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    THANK YOU GOD BLESS YOU!!!! GOODNIGHT

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