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anonymous
 5 years ago
Convert r=3sin(theta) into a cartesian equation.
anonymous
 5 years ago
Convert r=3sin(theta) into a cartesian equation.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[r=\sqrt (x^2+y^2)\] \[\tan^{1} (y/x)=\theta\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Put them in place, and try simplifying, the resulting equation will be in terms of x and y

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0No need to make it so complicated for θ. You should know that polar coordinates mean \[\sin θ = y\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0rsin(theta) = y. I just need to know how to deal with the r being on the left side of the equation basically.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Good point @nowhereman

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0a, right forgot that r

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0you can divide it away then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In r you can put r=(√x^2+y^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so you use the equation of a circle? Not sure exactly where that's coming from...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, you got to square the right side

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0That would just be the definition of polar coordinates. \[r = 3\sinθ ⇔ r = 3ry ⇔ 1 = 3y ∨ r = 0 ⇔ y = \frac 1 3 ∨ x = y = 0\]

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, that was math is about.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah I understand that but the pathetic American Education System doesn't go into the abstract much. So call me dumb but that's how it is. lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the graph of this thing is a circle centered on the yaxis stretching from the origin to the y=3 mark...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it should end up as: x^2 + (y 1/2)^2 = 3/2 if i see it right :)

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0mmh, yeah I put the r on the wrong side... guess I'm not awake after all

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Amistre, what was your process for getting that answer?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0seeing the graph in my head really :) the algebra is this: r = 3sin(t) ; * r r^2 = 3rsin(t) ; r^2 = x^2 + y^2 ; and rsin(t) = y x^2 + y^2 = 3y ; 3y x^2 +y^2 3y = 0 ; complete the square x^2 +y^2 3y + (3/2)^2 = (3/2)^2 ; clean up the square.. x^2 +(y3/2)^2 = (3/2)^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i was off by a y 1/2 the first time lol....but then again i am not right in the head ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok I think I'm beginning to see it. Thanks.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I may come up with another one in a minute. Just digesting it right now.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0at sin(0) we are at the origin; at sin(90) we are at 3; then we swing back to 0 on our way thru and that makes the circle that sits on the origin stretched to y=3 in my head

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0but yet i cant seem to get how to turn parametric equations into cartesian equation lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think I typed the right answer when I typed \[x^2+y^2=3y\] didn't I?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0iam; that was a good start yes :), just needed to turn it into the circle equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am not getting you, if we just write it as \[x^2+y^23 y = 0 \], then it represents a circle doesn't it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0been wondering how to make money doing this.... got $60 left in the bank.... :/

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that form is not the standard for a circle equation.... just needs dressed up a bit ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Huh? What do you mean?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0"been wondering how to make money doing this.... got $60 left in the bank.... :/"??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0just broke, thats all :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know some methods, but those are not similar to these

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0:) I saw something today about a cat.... but it looked used up...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0id be great if I could get a job tutoring at the college..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can help you if you want to tutor people online by getting paid at the same time

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thatd be good if it works out :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i got aloooottt of time, and aloooott of math in me lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you serious about it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I mean do you really want to do it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, this experience here has taught me that I am actually good at it :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So if you are interested, I can help you start, but you got to email me when you wish to begin

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0tony031172@gmail.com is my junkmmail catcher, I check it still, but it keeps my good email from the clutter...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have your email address, did you forget?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol.... just wasnt sure ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have your real email address a*******@*****.com

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0:) ill hit you up tomorrow, my borrowed time i up here at the library :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sure, I hope I am disturbing all of them who are sitting here
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