anonymous
  • anonymous
For sin(theta) = -0.4321, 0º < theta < 360º How many solutions are possible? In which quadrants would you find the solutions? Determine the reference angle for this equation to the nearest degree. Determine all the solutions to the equation to the nearest degree
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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dumbcow
  • dumbcow
There are 2 solutions - If you look at graph of sin, you notice it goes down from 0 to -1 then back up to 0, therefore it crosses value -.43 twice 3rd and 4th quadrant - see above arcsin(-0.4321) = -25.6 degrees = 360-25.6 = 334.4 since this is greater than 270 it is in 4th quadrant
anonymous
  • anonymous
this looks like a great solution :)
anonymous
  • anonymous
is the part below the answer to d? "arcsin(-0.4321) = -25.6 degrees = 360-25.6 = 334.4 since this is greater than 270 it is in 4th quadrant"

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dumbcow
  • dumbcow
yes its half the answer now to find the solution in 3rd quadrant add 25.6 to 180
anonymous
  • anonymous
study the sine graph
anonymous
  • anonymous
the reference angle is -25.6
anonymous
  • anonymous
thanks oodles!

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