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anonymous
 5 years ago
For sin(theta) = 0.4321, 0º < theta < 360º
How many solutions are possible?
In which quadrants would you find the solutions?
Determine the reference angle for this equation to the nearest degree.
Determine all the solutions to the equation to the nearest degree
anonymous
 5 years ago
For sin(theta) = 0.4321, 0º < theta < 360º How many solutions are possible? In which quadrants would you find the solutions? Determine the reference angle for this equation to the nearest degree. Determine all the solutions to the equation to the nearest degree

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0There are 2 solutions  If you look at graph of sin, you notice it goes down from 0 to 1 then back up to 0, therefore it crosses value .43 twice 3rd and 4th quadrant  see above arcsin(0.4321) = 25.6 degrees = 36025.6 = 334.4 since this is greater than 270 it is in 4th quadrant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this looks like a great solution :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is the part below the answer to d? "arcsin(0.4321) = 25.6 degrees = 36025.6 = 334.4 since this is greater than 270 it is in 4th quadrant"

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0yes its half the answer now to find the solution in 3rd quadrant add 25.6 to 180

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the reference angle is 25.6
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