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anonymous

  • 5 years ago

For sin(theta) = -0.4321, 0º < theta < 360º How many solutions are possible? In which quadrants would you find the solutions? Determine the reference angle for this equation to the nearest degree. Determine all the solutions to the equation to the nearest degree

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  1. dumbcow
    • 5 years ago
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    There are 2 solutions - If you look at graph of sin, you notice it goes down from 0 to -1 then back up to 0, therefore it crosses value -.43 twice 3rd and 4th quadrant - see above arcsin(-0.4321) = -25.6 degrees = 360-25.6 = 334.4 since this is greater than 270 it is in 4th quadrant

  2. anonymous
    • 5 years ago
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    this looks like a great solution :)

  3. anonymous
    • 5 years ago
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    is the part below the answer to d? "arcsin(-0.4321) = -25.6 degrees = 360-25.6 = 334.4 since this is greater than 270 it is in 4th quadrant"

  4. dumbcow
    • 5 years ago
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    yes its half the answer now to find the solution in 3rd quadrant add 25.6 to 180

  5. anonymous
    • 5 years ago
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    study the sine graph

  6. anonymous
    • 5 years ago
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    the reference angle is -25.6

  7. anonymous
    • 5 years ago
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    thanks oodles!

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