A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
simple trig identities problem!
Solve the following quadratic trig equations algebraically (without graphing technology) for the domain 0o < x < 360o. Use exact solutions whenever possible.
a) 6cos^2(theta ) + cos(theta )  1 = 0
b) 2  2sin^2( theta) = cos(theta )
anonymous
 5 years ago
simple trig identities problem! Solve the following quadratic trig equations algebraically (without graphing technology) for the domain 0o < x < 360o. Use exact solutions whenever possible. a) 6cos^2(theta ) + cos(theta )  1 = 0 b) 2  2sin^2( theta) = cos(theta )

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0put cos(theta) = x in the first equation and solve for x, and then substitute it back into cos theta

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for the second one 22sin^theta = 2(1sin^2theta) = 2 cos^2theta and then put cos theta = x and solve for x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm sorry but i don't understand any of that...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0substitute cos theta = x in the first problem and post what you got.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0as in.. 6x^2+x1?? like a quadratic?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so solve that quadratic equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont remember how to when the x^2 value has a coefficient..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find out and solve it. If you have done it before, I am sure you can solve it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well everything becomes a fraction if i factor out the 6.... that vid didnt help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.06x2+x1 = 6x2+3x2x1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright, so now what is the next step?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know how to factor quadratic equations?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0using the qudratic frmula? yes. why did i need to break up that middle term?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay. there is another way to solve quadratic eqns. its called factoring. so 6x2+3x2x1 = 3x(2x+1)1(2x+1) = (3x1)(2x+1)=0. so x = 1/3 or x = 1/2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, but how does this relate to the trig question? haha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if x = 1/3, it means cos theta = 1/3. and x= 1/2. so cos theta = 1/2. solve foe theta within 0 and 360 degrees

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wwhat do you mean by solving for theta between 0 and 360? sorry i'm so bad at this!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dont worry about the 0 and 360.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0post the values of theta you got.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0arent the x= values the solutions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, x is just a variable you used to denote cos theta. so you have to find theta
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.