I have a few problems where you are given a point and an equation and you have to find an equation that is either parallel or perpendicular. I just don't get it at all...

- anonymous

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- anonymous

parallel : the same slope
perpendicular : slope flip and opposite site

- anonymous

I know, but what am I to do with the points I'm given? Do I plug them in the equation or what? I'm confused.

- anonymous

give me a example

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## More answers

- anonymous

Okay. One of them is Find an equation of the line meeting the specified conditions. Write the final answer in slope-intercept form.
Containing the point (2,6) and parallel to y=-4x-1

- anonymous

y=-4x-1 if parallel use the same slope : -4
and creative another line
y -6 = -4(x - 2)
y -6 = -4x +8
y = -4x +8 +6
y = -4x + 14 now
line : y=-4x-1 parallel to line
y = -4x + 14

- anonymous

-4 is slope
14 is y intercept

- anonymous

how do you get the slope when there's only one given pair of points?

- anonymous

use the frist equation slope y=-4x-1
slope is -4

- anonymous

Okay. That makes so much more sense now. Thanks.

- anonymous

The slope between two points is
\(\frac{y_2-y_1}{x_2-x_1}\)

- anonymous

one given pair use slpoe = 6/2 or 3

- anonymous

If you have the equation for a line y = mx + b, m is the slope.

- anonymous

So, let's say I have one that has the points (0,-5) and perpendicular to y=6x + 8. How would I go about solving that?

- anonymous

What is the slope for that line y=6x+8?

- anonymous

given what I said before about m?

- anonymous

y=6x + 8 perpendicular use 6 flip = 1/6 and negative side is : - 1/6
y- (-5) =-1/6( x- 0)
y +5 = -1/6x
y = -1/6x -5
line: y=6x + 8 is: perpendicular to
y = -1/6x -5

- anonymous

Thanks so much. That has helped a lot.

- anonymous

you are welcome

- anonymous

Now, what if I have a problem where it only has y? For example, points (0,-9) and parallel to 4y=8

- anonymous

Solve for y.

- anonymous

If 4y=8 then y=?

- anonymous

I know y=2 but I'm lost as to what to do next

- anonymous

Ok, well. Going back to the form y=mx + b, what is your m?

- anonymous

would it be 0? or undefined?

- anonymous

It would be 0. y = 0x + 2 = 2

- anonymous

y=2 is a straight horizontal line that goes through the y axis at y=2 and doesn't increase or decrease with a change in x.

- anonymous

So the slope is 0. Now to find a new line that is parallel means that the new line has the same slope.

- anonymous

But instead of going through y=2, it goes through y=-9

- anonymous

I ended up with y=0x -9 but I'm not sure if that's right?

- anonymous

Yes, now simplify.

- anonymous

4y=8
y = 2 slope =0
y-9= 0(x-0)
y = 9
line 4y=8 parallel to line y = 9

- anonymous

Should be y=-9

- anonymous

y=-9 if you want perpendicular to line 4y=8

- anonymous

No. y=-9 is parallel to the line y=2. They both have a 0 slope. One intersects (0,-9) the other intersects (0,-9)

- anonymous

One intersects(0,-9) and the other intersects(0,2) rather

- anonymous

I also got y=-9

- anonymous

A perpendicular line would have an undefined slope -1/0

- anonymous

I forgot negative 9
y=-9 is right amswer

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