I have a few problems where you are given a point and an equation and you have to find an equation that is either parallel or perpendicular. I just don't get it at all...

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I have a few problems where you are given a point and an equation and you have to find an equation that is either parallel or perpendicular. I just don't get it at all...

Mathematics
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parallel : the same slope perpendicular : slope flip and opposite site
I know, but what am I to do with the points I'm given? Do I plug them in the equation or what? I'm confused.
give me a example

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Okay. One of them is Find an equation of the line meeting the specified conditions. Write the final answer in slope-intercept form. Containing the point (2,6) and parallel to y=-4x-1
y=-4x-1 if parallel use the same slope : -4 and creative another line y -6 = -4(x - 2) y -6 = -4x +8 y = -4x +8 +6 y = -4x + 14 now line : y=-4x-1 parallel to line y = -4x + 14
-4 is slope 14 is y intercept
how do you get the slope when there's only one given pair of points?
use the frist equation slope y=-4x-1 slope is -4
Okay. That makes so much more sense now. Thanks.
The slope between two points is \(\frac{y_2-y_1}{x_2-x_1}\)
one given pair use slpoe = 6/2 or 3
If you have the equation for a line y = mx + b, m is the slope.
So, let's say I have one that has the points (0,-5) and perpendicular to y=6x + 8. How would I go about solving that?
What is the slope for that line y=6x+8?
given what I said before about m?
y=6x + 8 perpendicular use 6 flip = 1/6 and negative side is : - 1/6 y- (-5) =-1/6( x- 0) y +5 = -1/6x y = -1/6x -5 line: y=6x + 8 is: perpendicular to y = -1/6x -5
Thanks so much. That has helped a lot.
you are welcome
Now, what if I have a problem where it only has y? For example, points (0,-9) and parallel to 4y=8
Solve for y.
If 4y=8 then y=?
I know y=2 but I'm lost as to what to do next
Ok, well. Going back to the form y=mx + b, what is your m?
would it be 0? or undefined?
It would be 0. y = 0x + 2 = 2
y=2 is a straight horizontal line that goes through the y axis at y=2 and doesn't increase or decrease with a change in x.
So the slope is 0. Now to find a new line that is parallel means that the new line has the same slope.
But instead of going through y=2, it goes through y=-9
I ended up with y=0x -9 but I'm not sure if that's right?
Yes, now simplify.
4y=8 y = 2 slope =0 y-9= 0(x-0) y = 9 line 4y=8 parallel to line y = 9
Should be y=-9
y=-9 if you want perpendicular to line 4y=8
No. y=-9 is parallel to the line y=2. They both have a 0 slope. One intersects (0,-9) the other intersects (0,-9)
One intersects(0,-9) and the other intersects(0,2) rather
I also got y=-9
A perpendicular line would have an undefined slope -1/0
I forgot negative 9 y=-9 is right amswer

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