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anonymous
 5 years ago
CAL 2:Find indefinite integral using simple substitution: Integral of (cosx/(1+(sinx)^2))dx
anonymous
 5 years ago
CAL 2:Find indefinite integral using simple substitution: Integral of (cosx/(1+(sinx)^2))dx

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits cosx/(1+(sinx)^2)dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes u=sin(x) du=cos(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{?}^{?}1/(u ^{2}+1)du\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0don't forgot constant )))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0full answer is arctan(sin(x))+const

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that simple? should I use first as denominator to change to 1+sin^2x and use identity?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lululz this aint sinh and cosh

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its called partly integration

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry it was not arctan it must be cotan

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right answer is cot(sin(x))+const

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok I was thinking:\[\int\limits cosx/1+(1\cos^2x) \to change given and than go from there but I see, \it would be more complicated\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its not cot it can't be I think inverse tan was right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0julia, where are you from?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and where do you study?
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