anonymous
  • anonymous
CAL 2:Find indefinite integral using simple substitution: Integral of (cosx/(1+(sinx)^2))dx
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\int\limits cosx/(1+(sinx)^2)dx\]
anonymous
  • anonymous
yes u=sin(x) du=cos(x)
anonymous
  • anonymous
\[\int\limits_{?}^{?}1/(u ^{2}+1)du\]

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anonymous
  • anonymous
it is arctan(u)
anonymous
  • anonymous
and u = sin(x)
anonymous
  • anonymous
don't forgot constant )))
anonymous
  • anonymous
full answer is arctan(sin(x))+const
anonymous
  • anonymous
that simple? should I use first as denominator to change to 1+sin^2x and use identity?
anonymous
  • anonymous
as sin^2x=1-cos^2x
anonymous
  • anonymous
no
anonymous
  • anonymous
lululz this aint sinh and cosh
anonymous
  • anonymous
its called partly integration
anonymous
  • anonymous
sorry it was not arctan it must be cotan
anonymous
  • anonymous
right answer is cot(sin(x))+const
anonymous
  • anonymous
ok I was thinking:\[\int\limits cosx/1+(1-\cos^2x) \to change given and than go from there but I see, \it would be more complicated\]
anonymous
  • anonymous
no don't this
anonymous
  • anonymous
its not cot it can't be I think inverse tan was right
anonymous
  • anonymous
no its cot=tan^-1
anonymous
  • anonymous
thank you
anonymous
  • anonymous
julia, where are you from?
anonymous
  • anonymous
if not secret =)
anonymous
  • anonymous
:O) Miami
anonymous
  • anonymous
and where do you study?

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