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1/(n^2+2n)=1/n-1/(2*(n+2))

oh yes
sorry

ineton good job guy

oops but not* all

yes never mind...i get it now....thanks so much!!!!!!

Ah, OK, I was typing it out :( But you're welcome.

are you asking about the sum of\[\sum_{0}^{\infty}{1 \over 2^n}\]?