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anonymous
 5 years ago
can anyone solve these problems???
M,A,M,J,J,A,S,O,..........What comes next?
a.N b.M c.A d.P
anonymous
 5 years ago
can anyone solve these problems??? M,A,M,J,J,A,S,O,..........What comes next? a.N b.M c.A d.P

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sathi, you posted a wrong problem, whats wrong with you,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the sequence is 3, 7, 31, 211

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so how did u prove that 3 , 7 31, 211

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the question was same in the exam paper. 31 not 32

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but anyway how did u solve that ..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you posted 32 , scroll to your question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0look at the problem you posted earlier you will find 32

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh... i mean 32 not 31

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, wait, admit that you posted an incorrect problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0look at the post , on the left, scroll down

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so the sequence 3, 7, 31, 211, is 1 + 2, 1 + 2 * 3 , 1 + 2 * 3 * 5 , 1 + 2*3*5*7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait, lets do the sequence

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is special about 2,3,5,7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the next number will be 1 + 2*3*5*7*11 = 2311

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea i agree with ur idea...thanks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you solve your MAMJAN problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its the series of month starting from M(march)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that a code, letters mean numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0X % of Y is Y % of : a.x b.y/100 c.x/100 d.100x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait, this is an open question, the sequence before are called euclid numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are there an an infinite number of prime euclid numbers, E6 is not prime for example

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey man m the student of medicine so i dont know the mathmatical calculation much more......so would u plz describe in simple way.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x% of y = x/ 100 * y = x * y/100 = y% of x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well another question.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in a class with a certain number of students , if one student weighing 50kg is added then average weight of class incereases by 1 kg ,if one more student weighin 50kg is added then the average weight of class increasses by 1.5kg over the original average? what isthe original average weight (in kg) of the class?
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