can anyone solve these problems???
M,A,M,J,J,A,S,O,..........What comes next?
a.N b.M c.A d.P

- anonymous

can anyone solve these problems???
M,A,M,J,J,A,S,O,..........What comes next?
a.N b.M c.A d.P

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- anonymous

sathi, you posted a wrong problem, whats wrong with you,

- anonymous

the sequence is 3, 7, 31, 211

- anonymous

NOT 3, 7, 32, 211,

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## More answers

- anonymous

so how did u prove that 3 , 7 31, 211

- anonymous

but the question was same in the exam paper.
31 not 32

- anonymous

but anyway how did u solve that ..

- anonymous

you posted 32 , scroll to your question

- anonymous

look at the problem you posted earlier you will find 32

- anonymous

oh... i mean 32 not 31

- anonymous

whats ur process

- anonymous

no, wait, admit that you posted an incorrect problem

- anonymous

ok...

- anonymous

look at the post , on the left, scroll down

- anonymous

follow me , one sec

- anonymous

wow i got answer

- anonymous

ok so the sequence 3, 7, 31, 211, is
1 + 2, 1 + 2 * 3 , 1 + 2 * 3 * 5 , 1 + 2*3*5*7

- anonymous

its option no.A...N

- anonymous

wait, lets do the sequence

- anonymous

what is special about 2,3,5,7

- anonymous

they are primes

- anonymous

so the next number will be 1 + 2*3*5*7*11 = 2311

- anonymous

2311, 30031, 510511

- anonymous

yea i agree with ur idea...thanks

- anonymous

how did you solve your MAMJAN problem?

- anonymous

its the series of month starting from M(march)

- anonymous

is that a code, letters mean numbers

- anonymous

haha

- anonymous

nice one

- anonymous

X % of Y is Y % of :
a.x b.y/100 c.x/100 d.100x

- anonymous

wait, this is an open question, the sequence before are called euclid numbers

- anonymous

are there an an infinite number of prime euclid numbers, E6 is not prime for example

- anonymous

hey man m the student of medicine so i dont know the mathmatical calculation much more......so would u plz describe in simple way.

- anonymous

my guess was a x

- anonymous

yes a

- anonymous

x is correct

- anonymous

but its c in book

- anonymous

x% of y = x/ 100 * y = x * y/100 = y% of x

- anonymous

oh , hmmmm

- anonymous

well another question.

- anonymous

in a class with a certain number of students , if one student weighing 50kg is added then average weight of class incereases by 1 kg ,if one more student weighin 50kg is added then the average weight of class increasses by 1.5kg over the original average? what isthe original average weight (in kg) of the class?

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