anonymous
  • anonymous
f(x)=-2/x^2+2x-3 Determine the domain of the function
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
domain is negative infinity to infinity but there should be some vertical asymptotes in there so it is not continuously from negative infinity to infinity. gimme a sec
dumbcow
  • dumbcow
x cannot be 0
anonymous
  • anonymous
no dumbcow, x cannot be -3 or 1

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anonymous
  • anonymous
domain should be x not equal to -1 or -3 i.e R-{-1,-3}
anonymous
  • anonymous
oh whoa nevermind didnt see the negative sign in front of the 2
anonymous
  • anonymous
and R here is the set of real numbers:)
anonymous
  • anonymous
got it?
anonymous
  • anonymous
x cannot be 0 thats it so all real numbers except when x is 0
anonymous
  • anonymous
I'm trying. lol. Thank you for explaining; I sure do appreciate it. Got tons of this stuff to help someone else out.
anonymous
  • anonymous
it doesnt make sense even if x=0 as there is a '-3' in th e denominator ...lol
anonymous
  • anonymous
this is unbelievable i must be drunk final answer is all real numbers except when x equals to 1 or -3
anonymous
  • anonymous
All numbers except wen x=-1 or -3....
anonymous
  • anonymous
of course x can equal to 0!!!!!!
anonymous
  • anonymous
no its 1 or -3 not -1 or -3
dumbcow
  • dumbcow
haha sorry you guys didnt read the problem correctly
anonymous
  • anonymous
yes it can be =0
anonymous
  • anonymous
yep
anonymous
  • anonymous
@dumbcow haha i hadnt the first time around either
anonymous
  • anonymous
now did u get it??
anonymous
  • anonymous
hello anybody there??
anonymous
  • anonymous
yes
anonymous
  • anonymous
so u got what i typed above?
anonymous
  • anonymous
Okay, so the domain is not (-inf, inf).....
anonymous
  • anonymous
no its not
anonymous
  • anonymous
So it's all real numbers except when x=0
anonymous
  • anonymous
no...its all real nos. except wen x=-1 or x=-3
anonymous
  • anonymous
now , is it alright?
anonymous
  • anonymous
Yes, thank you
anonymous
  • anonymous
you're welcome @JJ
anonymous
  • anonymous
So, if I had [f(x)=\sqrt{5-x}\] , would that mean, the Domain would be all real numbers? Just making sure I got that one right.I'm assuming this because I can plug anything in there.
anonymous
  • anonymous
no x cannot equal any negative number in that caase
anonymous
  • anonymous
u can plug anything there except the number/numbers that make the denominator go '0'
anonymous
  • anonymous
and yeah , sqrt can't be negative so u have to remeber that:) so domain wud be numbers<5
anonymous
  • anonymous
So, all real number <5
anonymous
  • anonymous
thinker i think youre a bit confused. x can equal indeed to 5, that would just mean y equals 0. The domain is R = (0,infinity)
anonymous
  • anonymous
I sure am confused. So sorry.
anonymous
  • anonymous
JJSONFIRE i am really off it today listen to thinker im wrong
anonymous
  • anonymous
Hey, trust me I understand.
anonymous
  • anonymous
yep youre right
anonymous
  • anonymous
hey ....if its(),infinity) that wud make the sqrt tern negative which is not Real!!
anonymous
  • anonymous
i know you do im admitting that im wrong. im tired but still willing to help
anonymous
  • anonymous
i just explained to you that i made a mistake
anonymous
  • anonymous
ive been working all day..... :/
anonymous
  • anonymous
yeah..thats ok...im tired too...nevermind
anonymous
  • anonymous
Do you think you guys could help me with one more..please
anonymous
  • anonymous
sure
anonymous
  • anonymous
This set of problems says I need to determine if "f" is defind by f(x)=2x^2+5. The problems are f(-2)............next is f(3x)............last is -f(x)............Please, explain the best you can ...i'm lost..the book is useless with explanations
anonymous
  • anonymous
just plug in -2 in the first one as it says "f(-2)"...in place of x & u will get the answer:) its simple:)
anonymous
  • anonymous
Wow, so i was right. Woohoo..
anonymous
  • anonymous
and similarly for the rest...if it says f(3x) then plug in '3x' in place of 'x' got it?
anonymous
  • anonymous
ohh u were..?? good:)
anonymous
  • anonymous
now i gotta go...bye...hope i helped u:)
anonymous
  • anonymous
i've been at this all night...not sure whats been right and whats been wrong.
anonymous
  • anonymous
ohh..dont worry thats how u learn, right?
anonymous
  • anonymous
ACtually, the one with the negative f...not so sure actually
anonymous
  • anonymous
hmm..np...bye for now:)
anonymous
  • anonymous
-f(x)....how in the world...Is it as simple as just writing that out?
anonymous
  • anonymous
hmmm yupp:)
anonymous
  • anonymous
Thank you sooooooooooo much.
anonymous
  • anonymous
ohhhhh:):) youre welcome:) hope i help u next time too:)
anonymous
  • anonymous
Oh, I have 2 more sets to finish that are different...need to finish them today. I am helping someone who seriously needs the help that will never use this stuff, so i'lm trying my very best to help them. Its very important it gets done right you know.
anonymous
  • anonymous
hmm yeah...but i am really tired:(:( sry:(:( gotta go...next time..
anonymous
  • anonymous
Thank you. Nite.
anonymous
  • anonymous
gud nite:):) n byee

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