A naval ship travels from Portsmouth, England to the west end of the Kiel Canal in northern Germany, and later returns to Portsmouth at a speed which is 10.25 km/h faster. Portsmouth is 820 km from the Kiel Canal. If the trip to the Kiel Canal takes 4 hours longer than the trip back to Portsmouth, find the speed of the ship in each direction and the total travel time.

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A naval ship travels from Portsmouth, England to the west end of the Kiel Canal in northern Germany, and later returns to Portsmouth at a speed which is 10.25 km/h faster. Portsmouth is 820 km from the Kiel Canal. If the trip to the Kiel Canal takes 4 hours longer than the trip back to Portsmouth, find the speed of the ship in each direction and the total travel time.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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ok just give me 2 mins
its pretty simple tho
thank you i don't understand it :( i don't like these type of problems :(

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the problem is pretty simple you just need a pen and a paper just visualise the ship as it is moving talking note of direction it give like a triangular or rectangular figure then you can go from there.....i sued to solve these things in 10th grade now im a college senior
so just follow my pattern
ive tried trust me, i just cant put them into perspective... anything else i can do but not these word ones :( i know horrible :(
ok following....
ok ill solve it and give you the solution just give me time
thank you so much, i greatly appreciate it
when you say time? do you mean a few times or later on during the day?
let x be the speed from England to Germany, so speed from G to E is x+10.25, because the ship return at 10.25km/h faster let y be the time going from G to E, so time from E to G is y+4 (4hrs longer) England to Germany Germany to England speed x km/h x+10.25 time y+4 y distance=speed * time so x(y+4)=820 y(x+10.25)=820 solve that get y=16 or y=-20 (not logical since time cant be negative) so y=16 -> x=41 then speed from England to Germany = 41km/h speed from Ger to End = 41+10.25=51.25 km/h
awesome... but what is the total travel time?
y+y+4=16+16+4=32 hrs
oh damn, 36 i mean
Let subscript 1 denote the trip there and subscript 2 denote the trip back. Velocity is simply distance divided by time. v1=d/t1=820/(4+x) with x being the time taken for the trip back.Since it tells you the trip is 4 hours longer than the trip back, naturally it is 4+x. v2=d/t2=820/x=v1+10.25 because it tells you the second trip is 10.25 faster so you have 2 equations for v2. Isolate for v1=820x/10.25 and equate it with the first v1 equation from before, so v1=820/x-10.25=820/(4+x). Solve for x which is 16. Plug x back into all equations and you have the speeds.
Great, thank you so much for your help, i greatly appreciate it
np

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