anonymous
  • anonymous
How do I find the second derivative of -1/sin ^2x ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
is it -1/sin^2 (x)
anonymous
  • anonymous
yes
anonymous
  • anonymous
i mean sin square x right?

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anonymous
  • anonymous
write 1 as sin^2x+cos^2x
anonymous
  • anonymous
it will become-(1+cot^2x)
anonymous
  • anonymous
u need help?
anonymous
  • anonymous
actually i was not able to post it on grp chat
anonymous
  • anonymous
@zain
anonymous
  • anonymous
I'd just change it to -csc^2(x) and then take the first derivative, and then chain rule for the second derivative
anonymous
  • anonymous
or else use uv rule
anonymous
  • anonymous
Thanks guys
anonymous
  • anonymous
taking 1=u & sinx =v & integrate
anonymous
  • anonymous
im sry...differentiate , (not integrate)
anonymous
  • anonymous
Differentiate by parts!! lol :)

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