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anonymous
 5 years ago
How do I find the second derivative of 1/sin ^2x ?
anonymous
 5 years ago
How do I find the second derivative of 1/sin ^2x ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean sin square x right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0write 1 as sin^2x+cos^2x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it will become(1+cot^2x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually i was not able to post it on grp chat

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'd just change it to csc^2(x) and then take the first derivative, and then chain rule for the second derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0taking 1=u & sinx =v & integrate

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im sry...differentiate , (not integrate)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Differentiate by parts!! lol :)
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