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anonymous
 5 years ago
When solving an exponential equation by graphing (Solve 4^7x+250) on a calculator, I keep getting x and y as zero at the intersection?
anonymous
 5 years ago
When solving an exponential equation by graphing (Solve 4^7x+250) on a calculator, I keep getting x and y as zero at the intersection?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0unless you move the graph by subtracting from it.... your never gonna hit the axis on an exponential function. They start from the left at just above zero and grow from there. At x=0, they alway cross at y=1 without modifying the equation.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your equation only has one intersecting point, (0,251)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and then theres the edit lol....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets log it out.... log4(4^7x) = log4(250) 7x = log4(250) log4(250) x =  7

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your point is going to be:  log4(250)    , 250   7 

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh I see how that would work. How would you do it on a calculator though? Our teacher said to go into "Y=" and set Y1=4^7x, and Y2=250. But then my graph has only one intersection at 0,0. X cant be zero because if you plug it back into the original equation, you'd get 4^7(0) which is 0=250. not correct....
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