Find dy/dx: y= 1/u^2 u=2x+3 I get 2x/(2x+3)^2

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Find dy/dx: y= 1/u^2 u=2x+3 I get 2x/(2x+3)^2

Mathematics
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-4/(2x+1)^3
plz help me

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I think you are in the wrong problem
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i need to write my health easy idont want to fial
this is math
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can you go to the english section
i posted my question plz
you posted your question in my math question
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if you go to "Home" at the top of the page and then click "English" I think, that is where you need to be
but theres no peole online yo help me i posted it 3x but no on helped me
I am a student just like you
To do these problems, I suggest utilize the chain rule as opposed to subbing in u into the original equation.
I got (2x+3)^-2 (2x) then i got my answer
y=1/u^2, rewrite as y=u^-2 to make it easier to differentiate. Using the chain rule. y'=-2u*u'. Find u' by differentiating u=2x+3 with respesct to x. Sub in u and u' into y'=-2u*u' and you have your solution.
plz
I really messed that one up. I don't know what I was doing. Now I get the answer: 1/(-2x-3)^3
you are missing a coefficienet of 4
ok I am going to take it step by step now: 1st step is to get u^-2 and 2
differentiate y to get y'=-2u^-3*u'. Substitute in u and u' and that's it.
yes then I get -2u^-3 (2) then -2(2x+3)^-3 (2) Am I good so far
yeah that's the right answer
ok then I get (-4x-6)^-3 (2) then I am wanting to make (-4x-6)^-3 into 2(-2x-3)^-3 This is where I think I am making the mistake
no you were already done. -2(2x+3)^-3 (2) is correct because the -2 multiples with the 2 to become -4. I don't really follow what you did in your last response
so will my answer be 2/-2(2x+3)^3
I feal like I need to do something with (2)
your -3 exponent is only applied to 2x+3 and not the -2, there is no need to bring it down
ok then it will be -4/(2x+3)^3
yes
Thank you for working through this problem with me and not just giving me the answer

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