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anonymous

  • 5 years ago

Find dy/dx: y= 1/u^2 u=2x+3 I get 2x/(2x+3)^2

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  1. anonymous
    • 5 years ago
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    the easy form is mus include : -name of a drug -history of drug -street name -short +long term effect -how is it ingested -what effects does it have on body -anyother intersting facts

  2. anonymous
    • 5 years ago
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    -4/(2x+1)^3

  3. anonymous
    • 5 years ago
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    plz help me

  4. anonymous
    • 5 years ago
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    i have to wirte an essay

  5. anonymous
    • 5 years ago
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    I think you are in the wrong problem

  6. anonymous
    • 5 years ago
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    what

  7. anonymous
    • 5 years ago
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    i need to write my health easy idont want to fial

  8. anonymous
    • 5 years ago
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    this is math

  9. anonymous
    • 5 years ago
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    idc

  10. anonymous
    • 5 years ago
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    can you go to the english section

  11. anonymous
    • 5 years ago
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    i posted my question plz

  12. anonymous
    • 5 years ago
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    you posted your question in my math question

  13. anonymous
    • 5 years ago
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    plz

  14. anonymous
    • 5 years ago
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    am sorry but can you help me

  15. anonymous
    • 5 years ago
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    plz

  16. anonymous
    • 5 years ago
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    if you go to "Home" at the top of the page and then click "English" I think, that is where you need to be

  17. anonymous
    • 5 years ago
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    but theres no peole online yo help me i posted it 3x but no on helped me

  18. anonymous
    • 5 years ago
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    I am a student just like you

  19. anonymous
    • 5 years ago
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    To do these problems, I suggest utilize the chain rule as opposed to subbing in u into the original equation.

  20. anonymous
    • 5 years ago
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    I got (2x+3)^-2 (2x) then i got my answer

  21. anonymous
    • 5 years ago
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    y=1/u^2, rewrite as y=u^-2 to make it easier to differentiate. Using the chain rule. y'=-2u*u'. Find u' by differentiating u=2x+3 with respesct to x. Sub in u and u' into y'=-2u*u' and you have your solution.

  22. anonymous
    • 5 years ago
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    plz

  23. anonymous
    • 5 years ago
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    I really messed that one up. I don't know what I was doing. Now I get the answer: 1/(-2x-3)^3

  24. anonymous
    • 5 years ago
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    you are missing a coefficienet of 4

  25. anonymous
    • 5 years ago
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    ok I am going to take it step by step now: 1st step is to get u^-2 and 2

  26. anonymous
    • 5 years ago
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    differentiate y to get y'=-2u^-3*u'. Substitute in u and u' and that's it.

  27. anonymous
    • 5 years ago
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    yes then I get -2u^-3 (2) then -2(2x+3)^-3 (2) Am I good so far

  28. anonymous
    • 5 years ago
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    yeah that's the right answer

  29. anonymous
    • 5 years ago
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    ok then I get (-4x-6)^-3 (2) then I am wanting to make (-4x-6)^-3 into 2(-2x-3)^-3 This is where I think I am making the mistake

  30. anonymous
    • 5 years ago
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    no you were already done. -2(2x+3)^-3 (2) is correct because the -2 multiples with the 2 to become -4. I don't really follow what you did in your last response

  31. anonymous
    • 5 years ago
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    so will my answer be 2/-2(2x+3)^3

  32. anonymous
    • 5 years ago
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    I feal like I need to do something with (2)

  33. anonymous
    • 5 years ago
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    your -3 exponent is only applied to 2x+3 and not the -2, there is no need to bring it down

  34. anonymous
    • 5 years ago
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    ok then it will be -4/(2x+3)^3

  35. anonymous
    • 5 years ago
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    yes

  36. anonymous
    • 5 years ago
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    Thank you for working through this problem with me and not just giving me the answer

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