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anonymous

  • 5 years ago

3logx=2 I need someone to explain what Im suppose to do??

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  1. anonymous
    • 5 years ago
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    solve for x. 3*log x = 2. divide by 3 on both sides log x = 2/3. solve for x.

  2. anonymous
    • 5 years ago
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    the value of x depends on your base.

  3. anonymous
    • 5 years ago
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    What do I need to do to solve for x?

  4. anonymous
    • 5 years ago
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    \[\log_{e}x = y \rightarrow x = e ^{y}\]

  5. anonymous
    • 5 years ago
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    so there is no answer??

  6. anonymous
    • 5 years ago
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    of course there is. I explained how to get x from log x in the previous post.

  7. anonymous
    • 5 years ago
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    Thanks for your help. I still dont understand, its just me. Thank you.

  8. anonymous
    • 5 years ago
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    log x = 2/3 ==> x = base^2/3. if it is natural log, then base is e. But in this case i think base is 10. so x = 10^2/3

  9. anonymous
    • 5 years ago
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    Is there something I should be punching in my caculator to get this answer?

  10. anonymous
    • 5 years ago
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    type 10^(2/3) in google

  11. anonymous
    • 5 years ago
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    copy and paste that exact phrase

  12. anonymous
    • 5 years ago
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    I did that and its giving me an answer of 4.??. I just wanted to know from logx=2/3 if there was something I needed to be doing on my cac. Thanks again.

  13. anonymous
    • 5 years ago
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    I dont know what calculator you have. Refer to the calculator instructions.

  14. anonymous
    • 5 years ago
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    I understand that. I was just looking for some basic steps to get from logx=2/3 to the answer of 10^2/3. Because I dont know what to do from there. I dont even know what to refer to in my cac, because Im not sure of the next step. BUR, I feel really really dumb, and Im sure Im just bothering you. Thanks

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