anonymous
  • anonymous
y=x^2+2 y=-x+4 SOMEONE PLEASE HELP ME ON THIS
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Equate the two equations, and then move everythign to one side so you have x^2+x-2. That factors into (x-1)^2=0, therefore x=1
anonymous
  • anonymous
Y=y, so x^2+2=-x+4 x^2+x-2=0 (x-1)(x+2)=0 x=1 or -2 Y=-x+4 y=-1+4. Or y=-(-2)+4 y=3 or y=6 so, x=1, y=3 or x=-2, y=6
anonymous
  • anonymous
@spaceknight ... after you get that 1 , do i plug that into x to get y ?

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anonymous
  • anonymous
&lotsobooks omg thanks . can you like tell me the steps on how you do it
anonymous
  • anonymous
lol oops i factored wrong sorry just listen to lotsobooks
anonymous
  • anonymous
i already solved this problem in the one before...
anonymous
  • anonymous
ok so can i ask you guys another question ? i need help on my entire algebra2 homework
anonymous
  • anonymous
you should try doing your own homework
anonymous
  • anonymous
&spaceknight i have been trying . if i knew how to do thiss i wouldntt be on my laptop asking for help . my teacher is the kind that doesnt like to explain too much .... I NEED HELP
anonymous
  • anonymous
Set both equations equal to one another. Move all of the terms to the left side of the equation by adding or subtracting the terms on both sides of the equation. Combine like terms. Since it is a quadratic equation, you can factor it - use FOIL backwards, sort of. Once you have the 2 possible values of x, then, you can substitute them back inti either of the original equations - I picked -x+4 since it is the easiest. Then, calculate the values of y. Remember to keep the x,y pairs together since they only go with one another.
anonymous
  • anonymous
see i never got instructions like that. ok how about this . im about to show you my next problem. im going to try and solve it by myself to see if i can do it but can you still help me
anonymous
  • anonymous
?
anonymous
  • anonymous
y=6x^2+5x+3 y==x+3
anonymous
  • anonymous
\[6x ^{2}+5x+3=-x+3\]
anonymous
  • anonymous
So far, so good.
anonymous
  • anonymous
ok so it will go like this i thinkk 6x^2+5x+3=-x+3 +x-3 +x-3 hold on i think i messed up
anonymous
  • anonymous
i got 6x^2+6x=0 when i subtracted
anonymous
  • anonymous
That is correct.
anonymous
  • anonymous
so what do i do now ?
anonymous
  • anonymous
In this case, it is easiest to subtract 6x from both sides.
anonymous
  • anonymous
then \[6x ^{2} = -6x ?\]
anonymous
  • anonymous
Right. Then, divide both sides by 6.
anonymous
  • anonymous
ok so then that is x^2 = -1x or x^2 = -x ?
anonymous
  • anonymous
Right. Now, divide both sides by x.
anonymous
  • anonymous
ok so then after that x = -1 ?
anonymous
  • anonymous
Right. Plug -1 into one of the original equations and solve for y.
anonymous
  • anonymous
so whenever i plug it into the second equation how do i do it ? do i ignore the negative there already is ?
anonymous
  • anonymous
No, keep the negative. -(-1)+3=
anonymous
  • anonymous
wouldnt that 1 just turn into a positive ?
anonymous
  • anonymous
Right.
anonymous
  • anonymous
ok so it would be 1+3 so y = 4 ?
anonymous
  • anonymous
Yep.
anonymous
  • anonymous
We missed a second solution when I had you subtract 6x from both sides.
anonymous
  • anonymous
you are AWESOMEEEE !!!! :p thanks for helping meee
anonymous
  • anonymous
what step did we miss ?
anonymous
  • anonymous
Not a step so much as another solution. At 6x^2+6x=0, it would have been better to factor 6x out. So, 6x (x+1)=0 x=-1 or x=0. then, y=4 or y=3.
anonymous
  • anonymous
You're welcome! Have fun!
anonymous
  • anonymous
:)

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