logx+log(3x-13)=1 I got the answer of 10/3 can someone see if that is right??

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logx+log(3x-13)=1 I got the answer of 10/3 can someone see if that is right??

Mathematics
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no it is wrong.
Ok, thank you.
log(3x2-13x) = 1 3x2-13x = 10

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I see what I did wrong. I put 26 instead of 13..
Wait.. no I didnt. Then I move the 10 over right?
giving me: 3x2-13-10=0 right?
right
Then I did the quadratic... maybe I did that wrong
3x2-15x+2x-10
where did you get the middle? -15x+2x?
-13x can be represented as -15x +2x.
why would I want to put that into my equation?
when I have 3x2-13x-10. Would you do the quadratic then?
is the answer 5
it is a method to factor the quadratic equation. 3x2-13x-10 = 0 3x2-15x+2x-10 = 0 3x(x-5)+2(x-5)= 0 ,factor out x-5, (x-5)(3x+2)=0. so, x= 5 and x = -3/2
got it!!! Thank you. I didnt notice it factored.
you should always see if a quadratic equation can be factored, it is much easier. If that fails, do the formula to solve
I usually do, my teacher just never gives us the ones that factor...lol.Thanks
you are welcome

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