anonymous
  • anonymous
Hello, I need help with an equation i did it, but it looks like it needs revision • A teacher is looking for the best option in purchasing school supplies for a classroom. Company A is offering a discount for every dollar amount spent; Company B is offering a higher discount than Company A, but the discount is applicable only for every dollar amount spent above $20. Determine which company will offer a better price based upon the dollar amount the teacher spends on school supplies.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
do you have a formula for determining the cost of each company? If you don't, develop a formula for each company, and then I can help you from there
anonymous
  • anonymous
yes i do there are three separate formulas y=0.8x y=0.7x+6 and y=x
anonymous
  • anonymous
I am having trouble with the excel graph, and i don't know if something is just not adding up

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anonymous
  • anonymous
I'm not sure what those equations correspond to
anonymous
  • anonymous
well, the discounts are 20% from Company A based on any amount purchased, and 30% from Company B for supplies purchased above $20.
anonymous
  • anonymous
ok, so when for the second one, when x is 20, y is twenty, and afterwards y = (x -20) * .7
anonymous
  • anonymous
sorry, y = (x - 20) * .7 + 20
anonymous
  • anonymous
yes but how do I put it in a graph? how do I find my points for those 3 equations? I attached an excel graph, but something isn't accurate
anonymous
  • anonymous
sorry, i can't open up the excel graph. but to solve the problem, you solve for the two equations i posted above
anonymous
  • anonymous
did you use scatter plot instead of line graph?
anonymous
  • anonymous
go to where you change chart type, and choose the segmented line, instead of the smooth curve under scatter plot
anonymous
  • anonymous
in the scatter chart?
anonymous
  • anonymous
Can I put any numbers to solve the equation, or how would I solve this equations above?
anonymous
  • anonymous
you see how two of the equations intersect on the graph?
anonymous
  • anonymous
yes, at 60, but at the bottom, i have a bump
anonymous
  • anonymous
these are the points that I use, 0, 20,40, 60,80
anonymous
  • anonymous
at x = 20, it will be discontinuous. it's supposed to be
anonymous
  • anonymous
x1 y1 x2 y2 0 0 0 0 20 16 20 20 40 32 30 27 60 48 40 34 80 64 60 48
anonymous
  • anonymous
i think something is wrong with the points that I'm using
anonymous
  • anonymous
use the equations i gave then
anonymous
  • anonymous
Are they the same as y=0.8x and 0.7x+6? Or can you regive me your equations if they are different?
anonymous
  • anonymous
why is it six and not 34? from 0 - 20, the equations should be y = .8 * x and y = x, after 20, it should be y = .8 x and y = .7 * x + 34
anonymous
  • anonymous
you know what, nevermind, the equation is right, i added 14 + 20 instead of subtracted
anonymous
  • anonymous
so your equations are correct
anonymous
  • anonymous
Whew, a relief since I have been working on them since yesterday. But my question is, what points do I use to plot the graph? How do I solve the equations?
anonymous
  • anonymous
I'm like math illiterate, which is probably why you're wondering why I'm having a hard time with these equations.
anonymous
  • anonymous
your points are correct, it shows exactly where the two graphs are equal. the only problem is, you chose to have the graph smooth the lines, instead of jagged. make them jagged
anonymous
  • anonymous
you see where it's curvy? it should just be an angle
anonymous
  • anonymous
how do I make them jagged? and do I need to do a point for the equation y=x
anonymous
  • anonymous
no, read up top, you need to change the graph type
anonymous
  • anonymous
look in excel where it has the types, where one is curved, and the other is jaggedy
anonymous
  • anonymous
So you can see my graph in front of you, does it make sense to you with both companies?
anonymous
  • anonymous
yes, it's fine, except that it's curved, and not jaggedy
anonymous
  • anonymous
in my excel, if i right click on the graph, and go to CHANGE CHART TYPE, i have the option on the bottom of the window to change it to a jagged scatter plot. other than that, it's supposed to have them cross like that, and the one is supposed to slightly change direction
anonymous
  • anonymous
Ok and how do I simultaneously solve those 3 equations?
anonymous
  • anonymous
you don't simultaneously solve all three
anonymous
  • anonymous
only the two, after x > 20
anonymous
  • anonymous
ok and how do I solve those 2? I'm sorry if I sound clueless, but I just don't understand math
anonymous
  • anonymous
you see how you have them already solved for y? you just set the right side of the one to the right side of the other, as in .8x = .7x+6, and solve for x
anonymous
  • anonymous
ok let me try that
anonymous
  • anonymous
x=60?
anonymous
  • anonymous
Would I be able to attach the file for the word problem so you can see if I did it right?
anonymous
  • anonymous
no, you did that right, but your answer doesn't match your data
anonymous
  • anonymous
so how do I fix it?
anonymous
  • anonymous
wait, is that your x or your y? your x is 60, and your y is 48?
anonymous
  • anonymous
yes
anonymous
  • anonymous
then you're done
anonymous
  • anonymous
So the equations with the graph are accurate?
anonymous
  • anonymous
This is what it asks for?
anonymous
  • anonymous
3. Solve the system of linear equations algebraically using either the substitution method or the elimination method to determine where the two cost options are equivalent, showing all work. a. Explain each step used to solve the system of linear equations. Include the following in your explanation: • The algebraic method used to solve the system of equations • All mathematical operations used to solve the system of equations • The solution of the system of equations
anonymous
  • anonymous
Which method did I use?
anonymous
  • anonymous
substitution
anonymous
  • anonymous
How did you come up with all three equations?
anonymous
  • anonymous
Are you there?

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