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anonymous

  • 5 years ago

Hello, I need help with an equation i did it, but it looks like it needs revision • A teacher is looking for the best option in purchasing school supplies for a classroom. Company A is offering a discount for every dollar amount spent; Company B is offering a higher discount than Company A, but the discount is applicable only for every dollar amount spent above $20. Determine which company will offer a better price based upon the dollar amount the teacher spends on school supplies.

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  1. anonymous
    • 5 years ago
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    do you have a formula for determining the cost of each company? If you don't, develop a formula for each company, and then I can help you from there

  2. anonymous
    • 5 years ago
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    yes i do there are three separate formulas y=0.8x y=0.7x+6 and y=x

  3. anonymous
    • 5 years ago
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    I am having trouble with the excel graph, and i don't know if something is just not adding up

  4. anonymous
    • 5 years ago
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    I'm not sure what those equations correspond to

  5. anonymous
    • 5 years ago
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    well, the discounts are 20% from Company A based on any amount purchased, and 30% from Company B for supplies purchased above $20.

  6. anonymous
    • 5 years ago
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    ok, so when for the second one, when x is 20, y is twenty, and afterwards y = (x -20) * .7

  7. anonymous
    • 5 years ago
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    sorry, y = (x - 20) * .7 + 20

  8. anonymous
    • 5 years ago
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    yes but how do I put it in a graph? how do I find my points for those 3 equations? I attached an excel graph, but something isn't accurate

  9. anonymous
    • 5 years ago
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    sorry, i can't open up the excel graph. but to solve the problem, you solve for the two equations i posted above

  10. anonymous
    • 5 years ago
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    did you use scatter plot instead of line graph?

  11. anonymous
    • 5 years ago
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    go to where you change chart type, and choose the segmented line, instead of the smooth curve under scatter plot

  12. anonymous
    • 5 years ago
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    in the scatter chart?

  13. anonymous
    • 5 years ago
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    Can I put any numbers to solve the equation, or how would I solve this equations above?

  14. anonymous
    • 5 years ago
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    you see how two of the equations intersect on the graph?

  15. anonymous
    • 5 years ago
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    yes, at 60, but at the bottom, i have a bump

  16. anonymous
    • 5 years ago
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    these are the points that I use, 0, 20,40, 60,80

  17. anonymous
    • 5 years ago
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    at x = 20, it will be discontinuous. it's supposed to be

  18. anonymous
    • 5 years ago
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    x1 y1 x2 y2 0 0 0 0 20 16 20 20 40 32 30 27 60 48 40 34 80 64 60 48

  19. anonymous
    • 5 years ago
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    i think something is wrong with the points that I'm using

  20. anonymous
    • 5 years ago
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    use the equations i gave then

  21. anonymous
    • 5 years ago
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    Are they the same as y=0.8x and 0.7x+6? Or can you regive me your equations if they are different?

  22. anonymous
    • 5 years ago
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    why is it six and not 34? from 0 - 20, the equations should be y = .8 * x and y = x, after 20, it should be y = .8 x and y = .7 * x + 34

  23. anonymous
    • 5 years ago
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    you know what, nevermind, the equation is right, i added 14 + 20 instead of subtracted

  24. anonymous
    • 5 years ago
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    so your equations are correct

  25. anonymous
    • 5 years ago
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    Whew, a relief since I have been working on them since yesterday. But my question is, what points do I use to plot the graph? How do I solve the equations?

  26. anonymous
    • 5 years ago
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    I'm like math illiterate, which is probably why you're wondering why I'm having a hard time with these equations.

  27. anonymous
    • 5 years ago
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    your points are correct, it shows exactly where the two graphs are equal. the only problem is, you chose to have the graph smooth the lines, instead of jagged. make them jagged

  28. anonymous
    • 5 years ago
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    you see where it's curvy? it should just be an angle

  29. anonymous
    • 5 years ago
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    how do I make them jagged? and do I need to do a point for the equation y=x

  30. anonymous
    • 5 years ago
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    no, read up top, you need to change the graph type

  31. anonymous
    • 5 years ago
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    look in excel where it has the types, where one is curved, and the other is jaggedy

  32. anonymous
    • 5 years ago
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    So you can see my graph in front of you, does it make sense to you with both companies?

  33. anonymous
    • 5 years ago
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    yes, it's fine, except that it's curved, and not jaggedy

  34. anonymous
    • 5 years ago
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    in my excel, if i right click on the graph, and go to CHANGE CHART TYPE, i have the option on the bottom of the window to change it to a jagged scatter plot. other than that, it's supposed to have them cross like that, and the one is supposed to slightly change direction

  35. anonymous
    • 5 years ago
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    Ok and how do I simultaneously solve those 3 equations?

  36. anonymous
    • 5 years ago
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    you don't simultaneously solve all three

  37. anonymous
    • 5 years ago
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    only the two, after x > 20

  38. anonymous
    • 5 years ago
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    ok and how do I solve those 2? I'm sorry if I sound clueless, but I just don't understand math

  39. anonymous
    • 5 years ago
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    you see how you have them already solved for y? you just set the right side of the one to the right side of the other, as in .8x = .7x+6, and solve for x

  40. anonymous
    • 5 years ago
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    ok let me try that

  41. anonymous
    • 5 years ago
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    x=60?

  42. anonymous
    • 5 years ago
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    Would I be able to attach the file for the word problem so you can see if I did it right?

  43. anonymous
    • 5 years ago
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    no, you did that right, but your answer doesn't match your data

  44. anonymous
    • 5 years ago
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    so how do I fix it?

  45. anonymous
    • 5 years ago
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    wait, is that your x or your y? your x is 60, and your y is 48?

  46. anonymous
    • 5 years ago
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    yes

  47. anonymous
    • 5 years ago
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    then you're done

  48. anonymous
    • 5 years ago
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    So the equations with the graph are accurate?

  49. anonymous
    • 5 years ago
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    This is what it asks for?

  50. anonymous
    • 5 years ago
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    3. Solve the system of linear equations algebraically using either the substitution method or the elimination method to determine where the two cost options are equivalent, showing all work. a. Explain each step used to solve the system of linear equations. Include the following in your explanation: • The algebraic method used to solve the system of equations • All mathematical operations used to solve the system of equations • The solution of the system of equations

  51. anonymous
    • 5 years ago
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    Which method did I use?

  52. anonymous
    • 5 years ago
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    substitution

  53. anonymous
    • 5 years ago
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    How did you come up with all three equations?

  54. anonymous
    • 5 years ago
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    Are you there?

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