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anonymous

  • 5 years ago

need help solving quadratic equation..

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  1. amistre64
    • 5 years ago
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    .... ..... .. .... . .. . .... .... .. . .... . (morse code)

  2. anonymous
    • 5 years ago
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    I need to consider this problem.. \[3x ^{2}+x-5=0\] And then use discriminant \[b ^{2}-4ac\] and then solve with the formula \[x=-b + or - \sqrt{b sqar-4ac} a\]

  3. anonymous
    • 5 years ago
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    haha morse code?....

  4. anonymous
    • 5 years ago
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    sorry that took so long, idk how to do the formula right on this thing.. does it kinda make sense though?

  5. anonymous
    • 5 years ago
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    ok so the squared part of that is all over 2a

  6. amistre64
    • 5 years ago
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    it makes sense :)

  7. anonymous
    • 5 years ago
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    lol ik haha

  8. myininaya
    • 5 years ago
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    do you mean \[x=(-b+\sqrt{b^2-4ac})/2 \] and \[x=(-b-\sqrt{b^2-4ac})/2 \]

  9. amistre64
    • 5 years ago
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    the discriminate gives us a +number, so there are 2 solutions

  10. myininaya
    • 5 years ago
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    why does it put the a so close to the x? its hard to read

  11. myininaya
    • 5 years ago
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    to c*

  12. amistre64
    • 5 years ago
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    -1/6 +- sqrt(61)/6

  13. myininaya
    • 5 years ago
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    yay i left out the time a in the denominator lol

  14. anonymous
    • 5 years ago
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    sorry my computer was being slow so everything you guys said just loaded.

  15. anonymous
    • 5 years ago
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    I left off with \[-1\sqrt{-59} all \over 6\]

  16. anonymous
    • 5 years ago
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    minus the all

  17. anonymous
    • 5 years ago
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    so i'm not sure if i do something with i at this point..or if that is even correct what I have.. if that was the answer someone gave up there I guess I'm not sure what that's supposed to look like typed out

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spraguer (Moderator)
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