quadratic equation.

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quadratic equation.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[2x ^{2}+x+2=0\] is the problem.. so far i am at \[-1\sqrt{-14}\over 4\]
the -1 isn't over 4 though... So I believe I am suposed to have 2 answers.. idk if they are non real or different real answers.. I need to determine that and find the answers..
oops. i meant -15 over 4

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anyone?
By using the qudratic equation, I get A = 2, B = 1, C = 2. You have it right. It is: \[-1 \pm \sqrt(-15)/4\] Since the answer in the square root is negative, it is a non-real answer or imaginary number with: \[(-1 \pm \sqrt(15 i) )\div 4\] I hope that helps...
i'm curious if my thing is frozen.. can someone type something so i know
thank you very much!

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