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anonymous

  • 5 years ago

quadratic equation.

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  1. anonymous
    • 5 years ago
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    \[2x ^{2}+x+2=0\] is the problem.. so far i am at \[-1\sqrt{-14}\over 4\]

  2. anonymous
    • 5 years ago
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    the -1 isn't over 4 though... So I believe I am suposed to have 2 answers.. idk if they are non real or different real answers.. I need to determine that and find the answers..

  3. anonymous
    • 5 years ago
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    oops. i meant -15 over 4

  4. anonymous
    • 5 years ago
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    anyone?

  5. anonymous
    • 5 years ago
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    By using the qudratic equation, I get A = 2, B = 1, C = 2. You have it right. It is: \[-1 \pm \sqrt(-15)/4\] Since the answer in the square root is negative, it is a non-real answer or imaginary number with: \[(-1 \pm \sqrt(15 i) )\div 4\] I hope that helps...

  6. anonymous
    • 5 years ago
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    i'm curious if my thing is frozen.. can someone type something so i know

  7. anonymous
    • 5 years ago
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    thank you very much!

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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