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anonymous
 5 years ago
A fitnss club charges members a monthly fee and a fee for each fitness class attended. Last month, one member attended 8 fitness classes and paid $80. Another member attendd 14 fitness classes and paid $98. Determine the monthly fee and the fee per fitness class.
anonymous
 5 years ago
A fitnss club charges members a monthly fee and a fee for each fitness class attended. Last month, one member attended 8 fitness classes and paid $80. Another member attendd 14 fitness classes and paid $98. Determine the monthly fee and the fee per fitness class.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So there's a monthly fee (let's call it 'F') and there's fixed perclassfee (how about 'C' ?) 1st mameber attends 8 classes and pays $80  so: \[8 C + F = $80\] 2nd member attends 14 classes and pays $98  so: \[14 C + F = $98\] so you got two equations in two unknowns. Think you can solve it on your own?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, please help through the rest :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use system of elimination to solve for C. 1*(8C + F) = 1*($80) *Multiply by 1 to eliminate F once you add the (14C + F) = $98 equations together So, you now have: 6C = 18 which means C = 3. *Plug those values into the original equations to solve for F. I hope that helps.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes it did actually, thanks a ton! =)
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