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anonymous

  • 5 years ago

x^4-7x^3-12x^2+176x-320 I have to give the exact values list multiple zeros as necessary so i just need to know the probably 4 zeros of this prob

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  1. myininaya
    • 5 years ago
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    x=4 is a zero

  2. myininaya
    • 5 years ago
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    so x^4-7x^3-12x^2+176x-320=(x-4)(x^3-3x-24x+80)=0

  3. anonymous
    • 5 years ago
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    there is more then 1 zero isnt there

  4. myininaya
    • 5 years ago
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    (x-4)(x^3-3x^2-24x+80)=0*

  5. myininaya
    • 5 years ago
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    yes there are 3 more

  6. anonymous
    • 5 years ago
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    nice!

  7. myininaya
    • 5 years ago
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    x=4 is again another zero

  8. myininaya
    • 5 years ago
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    (x-4)(x-4)(x^2+x-20)=0

  9. myininaya
    • 5 years ago
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    now we have 2 more to find

  10. anonymous
    • 5 years ago
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    +5 - 4

  11. myininaya
    • 5 years ago
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    -5,4

  12. anonymous
    • 5 years ago
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    oo ya i didnt factor them to 0

  13. myininaya
    • 5 years ago
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    because x^2+x-20=(x+5)(x-4)

  14. anonymous
    • 5 years ago
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    thank you !

  15. myininaya
    • 5 years ago
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    so 4 multiplicity 3 and 5

  16. myininaya
    • 5 years ago
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    oops -5

  17. myininaya
    • 5 years ago
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    np

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