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anonymous

  • 5 years ago

I need some help.. I've already done these problems and i got them back and they need fixed.. will someone please help me

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  1. anonymous
    • 5 years ago
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    what are they?

  2. anonymous
    • 5 years ago
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  3. anonymous
    • 5 years ago
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    on these three i need to find the surface area

  4. myininaya
    • 5 years ago
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    for the first one we have 4 triangles and a square. the area of a triangle is .5(base)(height) and the area of a square is (base)^2

  5. myininaya
    • 5 years ago
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    so we have 4(.5)(base)(height)+b^2

  6. anonymous
    • 5 years ago
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    well i redid the first one and i got 103.47

  7. myininaya
    • 5 years ago
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    =2(base)(height)+(base)^2=2(4.2)(10)+(4.2)^2 is this what you did?

  8. anonymous
    • 5 years ago
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    yea

  9. myininaya
    • 5 years ago
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    I got 101.64

  10. anonymous
    • 5 years ago
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    oh yeah that's what i meant..

  11. myininaya
    • 5 years ago
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    the second we have 4 triangles

  12. myininaya
    • 5 years ago
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    so we have 4 times .5(b)(h) since there are all congruent triangles

  13. myininaya
    • 5 years ago
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    =2bh

  14. myininaya
    • 5 years ago
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    =2(15)(9)=270

  15. myininaya
    • 5 years ago
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    it looks like you got a check mark on that one and the answer was 67.5?

  16. anonymous
    • 5 years ago
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    yea.. all the ones i post need fixed

  17. myininaya
    • 5 years ago
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    k

  18. myininaya
    • 5 years ago
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    does everything make sense so far?

  19. anonymous
    • 5 years ago
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    yeah

  20. myininaya
    • 5 years ago
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    ok lets look at the last one

  21. anonymous
    • 5 years ago
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    6 times .5bh

  22. myininaya
    • 5 years ago
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    yes there are 6 triangles and then there is that hexagon hex means 6 right?

  23. anonymous
    • 5 years ago
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    yea

  24. myininaya
    • 5 years ago
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    lets look at the triangles first the base 6 and we need to find the height

  25. myininaya
    • 5 years ago
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    thats if we look at one traingle

  26. myininaya
    • 5 years ago
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    if we divide a triangle and half we can from a right triangle so we can use the Pythagorean thm the hyp is 12 and if we divide the base in half the base is 3 or our newly formed triangle so we can find the height of the triangle let's call it h. we have 3^2+h^2=12^2 implies h=sqrt(135). so the area of the whole traingle is .5(6)(sqrt(135) since we have 6 trangles we have this area times 6 so this equals 18(sqrt(135)) but now we need to find the area of the hexagon

  27. myininaya
    • 5 years ago
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    if we draw two vertical lines from one vertex to another and one horizontal line from one vertex to another we would form 2 rectangles and 4 traingles

  28. myininaya
    • 5 years ago
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    looking at one triangle we see that the hyp is 6 and we know that the legs are equal. so we have b^2+b^2=6^2 imples 2b^2=36 implies b^2=18 implies b=sqrt(18) so the area of the triangle is .5(sqrt18)(sqrt(18)=.5(18)=9 since we have 4 of these triangles then we multiply the 9 by 4 =36 now we need to find the area of the rectangles we know 1 side =6 so we need find the length of the other side that runs perpendicular to it

  29. myininaya
    • 5 years ago
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    but we found that when we were finding the legs of the triangle above so the side running perpendicular to the 6cm side has length sqrt(18) so the area of the rectangle is (6)sqrt(18) but since we have 2 we multiply by 2 giving us 12sqrt(18) now we add all of our areas together

  30. myininaya
    • 5 years ago
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    so we have the area of the 6 triangles is 18sqrt(135) and we have the area of the hexagon is 12sqrt(18)+36 the total surface area is 18sqrt(135)+12sqrt(18)+36

  31. anonymous
    • 5 years ago
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    so 974.22

  32. myininaya
    • 5 years ago
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    i got 296.05

  33. anonymous
    • 5 years ago
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    i did my math wrong..

  34. anonymous
    • 5 years ago
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    but thank u

  35. myininaya
    • 5 years ago
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    that last problem was really long I hope i'm right lol

  36. anonymous
    • 5 years ago
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    can help me with some more

  37. myininaya
    • 5 years ago
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    more surface area?

  38. anonymous
    • 5 years ago
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    no volume

  39. myininaya
    • 5 years ago
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    ok i will look at one more and then i have to leave

  40. anonymous
    • 5 years ago
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    the first three are finding volume

  41. myininaya
    • 5 years ago
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    ok the first one we need to find the area of the base and multiply by the height of the solid

  42. myininaya
    • 5 years ago
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    the area of the base is .5(b)(h)=.5(6)(8)=24 the height of the solid is 10 so 24(10)=240

  43. myininaya
    • 5 years ago
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    the second one you shouldnt had divided by 3 it should had been 2

  44. myininaya
    • 5 years ago
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    the last one you set it up right but you should had got 3451.04

  45. anonymous
    • 5 years ago
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    okay thank you

  46. myininaya
    • 5 years ago
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    np i hope i was a help

  47. anonymous
    • 5 years ago
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    ur were

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