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You can either factor or use the quadratic formula.
I am not quite sure how to do that.
This one is factorable, so lets do that.
Because it is an x^2 with no number multiplied by it, we know it will be in the form (x+?)(x+?)
Have you done FOIL yet?
No I have no idea what that is
If we have something like this (x-4)(x+3) you can expand it by using a method called FOIL.
First Outside Inside Last
you multiply the terms like that and add them together
in this example, we would end up with x^2 +3x -4x -12
which simplifies to x^2 -x -12
Now, notice that that looks a whole lot like the problem you started with! We are going to do FOIL backwards.
X^2+6x-40 we are looking for two numbers that when multiplied give us -40, but when added give us 6.
they can be positive or negative, and they'll be integers in a basic problem such as this. Any numbers come to mind?
How about 4 and -10?
So, we end up with this: (x+4)(x-10) When FOILed, we get this: X^2+6x-40 Remember, this is set equal to zero so we have ended up with (x+4)(x-10)=0
Now we can solve it. This equals zero when x is either -4 or 10.
This is how I got that: you can set both parts equal to zero: x-4=0 x+10=0 solving, we get x to equal -4 and 10.
oops, i meant this: This is how I got that: you can set both parts equal to zero: x+4=0 x-10=0 solving, we get x to equal -4 and 10. Quadratic equations like these have two answers the majority of the time, so the answer would be x=-4, 10
err, scratch that
Back when I first said "How about 4 and -10?" I got the signs backwards. So x actually comes out to equal 4 and -10 in the end... sorry
Did you get all that? Kinda confusing the first time around...
It's fine. Thank you for your help! I really appreciate it. I kind of understand. Im pretty bad at math.