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anonymous
 5 years ago
Solve for x, X^2+6x40=0
anonymous
 5 years ago
Solve for x, X^2+6x40=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can either factor or use the quadratic formula.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am not quite sure how to do that.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This one is factorable, so lets do that.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Because it is an x^2 with no number multiplied by it, we know it will be in the form (x+?)(x+?)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Have you done FOIL yet?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No I have no idea what that is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If we have something like this (x4)(x+3) you can expand it by using a method called FOIL.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First Outside Inside Last

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you multiply the terms like that and add them together

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in this example, we would end up with x^2 +3x 4x 12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which simplifies to x^2 x 12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now, notice that that looks a whole lot like the problem you started with! We are going to do FOIL backwards.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0X^2+6x40 we are looking for two numbers that when multiplied give us 40, but when added give us 6.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0they can be positive or negative, and they'll be integers in a basic problem such as this. Any numbers come to mind?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, we end up with this: (x+4)(x10) When FOILed, we get this: X^2+6x40 Remember, this is set equal to zero so we have ended up with (x+4)(x10)=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now we can solve it. This equals zero when x is either 4 or 10.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is how I got that: you can set both parts equal to zero: x4=0 x+10=0 solving, we get x to equal 4 and 10.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops, i meant this: This is how I got that: you can set both parts equal to zero: x+4=0 x10=0 solving, we get x to equal 4 and 10. Quadratic equations like these have two answers the majority of the time, so the answer would be x=4, 10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Back when I first said "How about 4 and 10?" I got the signs backwards. So x actually comes out to equal 4 and 10 in the end... sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Did you get all that? Kinda confusing the first time around...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's fine. Thank you for your help! I really appreciate it. I kind of understand. Im pretty bad at math.
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