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anonymous
 5 years ago
Find the antiderivative of
anonymous
 5 years ago
Find the antiderivative of

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[f(x) = x/(x ^{2} + 1)^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that appears to be an arctan

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 + 1 = 2x we need a 2 up top to ln(x) it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0multiply by 1; or rather 2/2 keep the top but pull out the 1/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that might not be good tho :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x  (x^2 +1)^2 tan the bottom :) maybe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0*alternate method time* 1/2 * f 2x/(x^4+1) u=x^2 du=2x a=1 arctan(x^2)+C

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0tan(t) = x tan^2(t) = x^2 tan^2 + 1 = sec^2 sec^2^2 = sec^4 tan(t) sec^4(t)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here is the rule I used:

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0tan(t) sec^4(t) maybe :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0my way you would still have to convert dx to dt...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{ }^{ }1/ (a^2+u^2) = 1/a \arctan(u/a)+C\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, that equation looks terrible...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0tan(t) = x dt sec^2 = dx thats helpful to me i think

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0[S] tan(t) sec^2(t) dt ....maybe

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0tan = sin/cos = sin sec1..... mines just messy lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Isn't that straight u substitution? f(x) = x (x^2 + 1) ^ 2 Let u= x^2 + 1 and du = 2x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That would give you...\[^{} \int\limits_{}^{} 1/2u ^{2}du\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I mean 2 as the expontent

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01/2u = 1/2(x^2+1) +C

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1/2\int\limits_{}^{}u ^{2}du\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0=1/(2u) + C, then substitue x^2 + 1 back in for u
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