anonymous
  • anonymous
I need some help.. I've already done these problems and i got them back and they need fixed.. will someone please help me
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
find the surface area of the solids. the pyramids are regular and the prisms, cylinders, and cones are right
anonymous
  • anonymous
For the first one, you can find the surface area of the cylinder part ( the part that looks like a can) by using 2(pi)r * height
anonymous
  • anonymous
Then add the area of the bottom circle (pi)r^2

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anonymous
  • anonymous
and then add SA of the cone, pi*r*s s is the slant height
anonymous
  • anonymous
thats what i did and i got 211.95cmin^2
anonymous
  • anonymous
ok, let me try and work it out with the numbers, just a sec
anonymous
  • anonymous
Do you know the right answer?
anonymous
  • anonymous
no
anonymous
  • anonymous
I got 203.47cm^2
anonymous
  • anonymous
wekkm 203.58 cm^2 when I use the pi button
anonymous
  • anonymous
oops, I mean "well"
anonymous
  • anonymous
for the cylinder, it's 30.6pi, the circle base is 9pi, and the cone is 25.2pi
anonymous
  • anonymous
so it would be 30.6pi+9pi+25.2pi
anonymous
  • anonymous
yes, and with that I got 64.8pi
anonymous
  • anonymous
For the 2nd picture, there are 6 sides that are rectangles, so that would be 6(base*height). I can't tell in the picture, is the height of each triangle 5, or what does the 5 go to?
anonymous
  • anonymous
to the slant eight of the triangle
anonymous
  • anonymous
height*
anonymous
  • anonymous
6 there are 6 triangles, each with a base of 3 and slant height of 5.....that would be 6 * 1/2 (base * height)
anonymous
  • anonymous
So, 6(3*6) +6(1/2)(3*5)
anonymous
  • anonymous
and then would you have to add the area of the base?
anonymous
  • anonymous
855+64.8pi
anonymous
  • anonymous
where did you get 855?
anonymous
  • anonymous
6(3*6) +6(1/2)(3*5)
anonymous
  • anonymous
6(3*12) +6(1/2)(3*5) that would be a 12 in the first ( )
anonymous
  • anonymous
153
anonymous
  • anonymous
64.8pi went to the first drawing...the one above is for the 2nd picture
anonymous
  • anonymous
I get 261 in^2
anonymous
  • anonymous
i thought the first pic was 203.58cm^2
anonymous
  • anonymous
yes, that's what I got....it was 64.8pi, which = 203.58cm^2
anonymous
  • anonymous
ok
anonymous
  • anonymous
for the 2nd drawing I get 261in^2 + area of that hexagon base
anonymous
  • anonymous
261 in^2 so this is the second pic surface area?
anonymous
  • anonymous
yes, but I dont' know how to find area of the base
anonymous
  • anonymous
will u help me with some other ones that ive already done i just got them wrong
anonymous
  • anonymous
i will try
anonymous
  • anonymous
okay.. for this one i needed to find the value of x.. and i got 3
1 Attachment
anonymous
  • anonymous
v=1/3 pi r^2 h
anonymous
  • anonymous
I get 3 also
anonymous
  • anonymous
so redoing it i get \[56.5=1/3\times \pi \times x ^{2}\times6\]
anonymous
  • anonymous
3 meters
anonymous
  • anonymous
\[56.5=6.28x ^{2}\]
anonymous
  • anonymous
yes, i get that too
anonymous
  • anonymous
Did it count off because you didn't put meters?
anonymous
  • anonymous
maybe
anonymous
  • anonymous
oh, wait, is x the diameter? We only found the radius.
anonymous
  • anonymous
so x = 6 meters
anonymous
  • anonymous
56.5/6.28=8.996
anonymous
  • anonymous
yeah, then sq rt of that gives the radius of that circle as 3 meters
anonymous
  • anonymous
but in the drawing, the x represents the diameter, which would be twice the radius, or 6 meters
anonymous
  • anonymous
I've got to go....good luck!
anonymous
  • anonymous
thank u
anonymous
  • anonymous
you're welcome

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