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anonymous

  • 5 years ago

I need some help.. I've already done these problems and i got them back and they need fixed.. will someone please help me

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  1. anonymous
    • 5 years ago
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    find the surface area of the solids. the pyramids are regular and the prisms, cylinders, and cones are right

  2. anonymous
    • 5 years ago
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    For the first one, you can find the surface area of the cylinder part ( the part that looks like a can) by using 2(pi)r * height

  3. anonymous
    • 5 years ago
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    Then add the area of the bottom circle (pi)r^2

  4. anonymous
    • 5 years ago
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    and then add SA of the cone, pi*r*s s is the slant height

  5. anonymous
    • 5 years ago
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    thats what i did and i got 211.95cmin^2

  6. anonymous
    • 5 years ago
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    ok, let me try and work it out with the numbers, just a sec

  7. anonymous
    • 5 years ago
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    Do you know the right answer?

  8. anonymous
    • 5 years ago
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    no

  9. anonymous
    • 5 years ago
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    I got 203.47cm^2

  10. anonymous
    • 5 years ago
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    wekkm 203.58 cm^2 when I use the pi button

  11. anonymous
    • 5 years ago
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    oops, I mean "well"

  12. anonymous
    • 5 years ago
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    for the cylinder, it's 30.6pi, the circle base is 9pi, and the cone is 25.2pi

  13. anonymous
    • 5 years ago
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    so it would be 30.6pi+9pi+25.2pi

  14. anonymous
    • 5 years ago
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    yes, and with that I got 64.8pi

  15. anonymous
    • 5 years ago
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    For the 2nd picture, there are 6 sides that are rectangles, so that would be 6(base*height). I can't tell in the picture, is the height of each triangle 5, or what does the 5 go to?

  16. anonymous
    • 5 years ago
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    to the slant eight of the triangle

  17. anonymous
    • 5 years ago
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    height*

  18. anonymous
    • 5 years ago
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    6 there are 6 triangles, each with a base of 3 and slant height of 5.....that would be 6 * 1/2 (base * height)

  19. anonymous
    • 5 years ago
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    So, 6(3*6) +6(1/2)(3*5)

  20. anonymous
    • 5 years ago
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    and then would you have to add the area of the base?

  21. anonymous
    • 5 years ago
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    855+64.8pi

  22. anonymous
    • 5 years ago
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    where did you get 855?

  23. anonymous
    • 5 years ago
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    6(3*6) +6(1/2)(3*5)

  24. anonymous
    • 5 years ago
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    6(3*12) +6(1/2)(3*5) that would be a 12 in the first ( )

  25. anonymous
    • 5 years ago
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    153

  26. anonymous
    • 5 years ago
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    64.8pi went to the first drawing...the one above is for the 2nd picture

  27. anonymous
    • 5 years ago
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    I get 261 in^2

  28. anonymous
    • 5 years ago
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    i thought the first pic was 203.58cm^2

  29. anonymous
    • 5 years ago
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    yes, that's what I got....it was 64.8pi, which = 203.58cm^2

  30. anonymous
    • 5 years ago
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    ok

  31. anonymous
    • 5 years ago
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    for the 2nd drawing I get 261in^2 + area of that hexagon base

  32. anonymous
    • 5 years ago
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    261 in^2 so this is the second pic surface area?

  33. anonymous
    • 5 years ago
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    yes, but I dont' know how to find area of the base

  34. anonymous
    • 5 years ago
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    will u help me with some other ones that ive already done i just got them wrong

  35. anonymous
    • 5 years ago
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    i will try

  36. anonymous
    • 5 years ago
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    okay.. for this one i needed to find the value of x.. and i got 3

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  37. anonymous
    • 5 years ago
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    v=1/3 pi r^2 h

  38. anonymous
    • 5 years ago
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    I get 3 also

  39. anonymous
    • 5 years ago
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    so redoing it i get \[56.5=1/3\times \pi \times x ^{2}\times6\]

  40. anonymous
    • 5 years ago
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    3 meters

  41. anonymous
    • 5 years ago
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    \[56.5=6.28x ^{2}\]

  42. anonymous
    • 5 years ago
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    yes, i get that too

  43. anonymous
    • 5 years ago
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    Did it count off because you didn't put meters?

  44. anonymous
    • 5 years ago
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    maybe

  45. anonymous
    • 5 years ago
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    oh, wait, is x the diameter? We only found the radius.

  46. anonymous
    • 5 years ago
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    so x = 6 meters

  47. anonymous
    • 5 years ago
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    56.5/6.28=8.996

  48. anonymous
    • 5 years ago
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    yeah, then sq rt of that gives the radius of that circle as 3 meters

  49. anonymous
    • 5 years ago
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    but in the drawing, the x represents the diameter, which would be twice the radius, or 6 meters

  50. anonymous
    • 5 years ago
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    I've got to go....good luck!

  51. anonymous
    • 5 years ago
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    thank u

  52. anonymous
    • 5 years ago
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    you're welcome

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