I need some help.. I've already done these problems and i got them back and they need fixed.. will someone please help me

- anonymous

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

find the surface area of the solids. the pyramids are regular and the prisms, cylinders, and cones are right

##### 2 Attachments

- anonymous

For the first one, you can find the surface area of the cylinder part ( the part that looks like a can) by using 2(pi)r * height

- anonymous

Then add the area of the bottom circle (pi)r^2

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

and then add SA of the cone, pi*r*s
s is the slant height

- anonymous

thats what i did and i got 211.95cmin^2

- anonymous

ok, let me try and work it out with the numbers, just a sec

- anonymous

Do you know the right answer?

- anonymous

no

- anonymous

I got 203.47cm^2

- anonymous

wekkm 203.58 cm^2 when I use the pi button

- anonymous

oops, I mean "well"

- anonymous

for the cylinder, it's 30.6pi, the circle base is 9pi, and the cone is 25.2pi

- anonymous

so it would be 30.6pi+9pi+25.2pi

- anonymous

yes, and with that I got 64.8pi

- anonymous

For the 2nd picture, there are 6 sides that are rectangles, so that would be 6(base*height).
I can't tell in the picture, is the height of each triangle 5, or what does the 5 go to?

- anonymous

to the slant eight of the triangle

- anonymous

height*

- anonymous

6 there are 6 triangles, each with a base of 3 and slant height of 5.....that would be 6 * 1/2 (base * height)

- anonymous

So, 6(3*6) +6(1/2)(3*5)

- anonymous

and then would you have to add the area of the base?

- anonymous

855+64.8pi

- anonymous

where did you get 855?

- anonymous

6(3*6) +6(1/2)(3*5)

- anonymous

6(3*12) +6(1/2)(3*5)
that would be a 12 in the first ( )

- anonymous

153

- anonymous

64.8pi went to the first drawing...the one above is for the 2nd picture

- anonymous

I get 261 in^2

- anonymous

i thought the first pic was 203.58cm^2

- anonymous

yes, that's what I got....it was 64.8pi, which = 203.58cm^2

- anonymous

ok

- anonymous

for the 2nd drawing I get 261in^2 + area of that hexagon base

- anonymous

261 in^2 so this is the second pic surface area?

- anonymous

yes, but I dont' know how to find area of the base

- anonymous

will u help me with some other ones that ive already done i just got them wrong

- anonymous

i will try

- anonymous

okay.. for this one i needed to find the value of x.. and i got 3

##### 1 Attachment

- anonymous

v=1/3 pi r^2 h

- anonymous

I get 3 also

- anonymous

so redoing it i get \[56.5=1/3\times \pi \times x ^{2}\times6\]

- anonymous

3 meters

- anonymous

\[56.5=6.28x ^{2}\]

- anonymous

yes, i get that too

- anonymous

Did it count off because you didn't put meters?

- anonymous

maybe

- anonymous

oh, wait, is x the diameter? We only found the radius.

- anonymous

so x = 6 meters

- anonymous

56.5/6.28=8.996

- anonymous

yeah, then sq rt of that gives the radius of that circle as 3 meters

- anonymous

but in the drawing, the x represents the diameter, which would be twice the radius, or 6 meters

- anonymous

I've got to go....good luck!

- anonymous

thank u

- anonymous

you're welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.