Use the quadratic formula to find the zeros of the function. y = 16x2 + 40x + 25
A. {-1.25, 1.25}
B. {-1.25}
C. {-4, 5}
D. {-0.8}

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Quadratic formula \[(-b \pm \sqrt{b^2-4ac})/2a\]
where a, b, c
\[ax^2+bx+c=0\]

Can you see why you need to use the quadratic formula now?

ok Go on the steps to solve it confuse me cuz there so long.

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