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anonymous
 5 years ago
Use the quadratic formula to find the zeros of the function. y = 16x2 + 40x + 25
A. {1.25, 1.25}
B. {1.25}
C. {4, 5}
D. {0.8}
anonymous
 5 years ago
Use the quadratic formula to find the zeros of the function. y = 16x2 + 40x + 25 A. {1.25, 1.25} B. {1.25} C. {4, 5} D. {0.8}

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Quadratic formula \[(b \pm \sqrt{b^24ac})/2a\] where a, b, c \[ax^2+bx+c=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you see why you need to use the quadratic formula now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok Go on the steps to solve it confuse me cuz there so long.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so in your case, 16=a, 40=b, 25=c. Plug them into the equation that Romero showed you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You want to find the zeros of function Y right? that means y=0 first do that you get \[16x^2+40x+25=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0mkay wow go on that makes so much more sense than anything my teachers are saying does

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0like jessie said a =16 b=40 c=25 now plug them in the equation I gave you on top.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok then i will then what do i do u dont have to give me the answer i just need the simple non confusing steps ur giving me.... ^^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The \[\pm\]means that you have to do one with + and one with  so it makes sense that you should get two values. You should be able to plug them in and whatever you get is the answer for X

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok ill plug them in for you but you work it out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i will i dont need the answer! lol just the steps!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a= 16 b=40 c=25 \[x= (b \pm \sqrt{b^24ac})/2a\] so if I plug them in I get \[x= (40 + \sqrt{40^24*16*25})/(2*16)\] \[x= (40  \sqrt{40^24*16*25}) / (2*16) \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so just do all the multiplication division etc and you should get your answers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OH!!!! Ok thank you thank you!! xD

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I plugged the first numbers in and then i got 8.75 as my answer... but thats not on the options!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i did!! thats why it took so long!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ignore the rest, and look under the radical. Start 40^2, which is 1600. Then look at the rest of what is under the radical. Do 4x16x25. Do you get 1600? So the square root of 16001600 is 0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are we good to there?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i didnt get the 1600 part for the first part i accidentally

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0put 4 because i squared the 40 then wasnt thinking and then i got the square root which was.. 40

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so then would you do 40 + 32 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well remember, 2x16 is 32, but your not adding, you are dividing.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So You would have 40 plus the square root of all that junk that turned out to be zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhhhh so u dont add?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow ok thx i didnt even see that!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No. At the end, you set your equation OVER 2a. In other words, divide it by 2a.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.regentsprep.org/Regents/math/algtrig/ATE3/quadsongs.htm memorize the equation, if you're in Algerbra or Algerbra 2 you're gonna use it again!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thx!!! ya im in Algebra IIthe only reason im bad is because of all the confusing steps!!!! :P but thx u helped me ALOT!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait wait so i wrote the problem down like this: x = (b +  Square root of… B^2 – 4ac /2a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and then were we doing b^2  4ac or somethin?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0bc i didnt understand why i would divide by 2a again which was 32

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait ok im confused UGH! i thought i got it!!!
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