anonymous
  • anonymous
Use the quadratic formula to find the zeros of the function. y = 16x2 + 40x + 25 A. {-1.25, 1.25} B. {-1.25} C. {-4, 5} D. {-0.8}
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Quadratic formula \[(-b \pm \sqrt{b^2-4ac})/2a\] where a, b, c \[ax^2+bx+c=0\]
anonymous
  • anonymous
Can you see why you need to use the quadratic formula now?
anonymous
  • anonymous
ok Go on the steps to solve it confuse me cuz there so long.

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anonymous
  • anonymous
so in your case, 16=a, 40=b, 25=c. Plug them into the equation that Romero showed you.
anonymous
  • anonymous
You want to find the zeros of function Y right? that means y=0 first do that you get \[16x^2+40x+25=0\]
anonymous
  • anonymous
mkay wow go on that makes so much more sense than anything my teachers are saying does
anonymous
  • anonymous
like jessie said a =16 b=40 c=25 now plug them in the equation I gave you on top.
anonymous
  • anonymous
ok then i will then what do i do u dont have to give me the answer i just need the simple non confusing steps ur giving me.... ^^
anonymous
  • anonymous
The \[\pm\]means that you have to do one with + and one with - so it makes sense that you should get two values. You should be able to plug them in and whatever you get is the answer for X
anonymous
  • anonymous
ok ill plug them in for you but you work it out
anonymous
  • anonymous
ok i will i dont need the answer! lol just the steps!
anonymous
  • anonymous
a= 16 b=40 c=25 \[x= (-b \pm \sqrt{b^2-4ac})/2a\] so if I plug them in I get \[x= (-40 + \sqrt{40^2-4*16*25})/(2*16)\] \[x= (-40 - \sqrt{40^2-4*16*25}) / (2*16) \]
anonymous
  • anonymous
so just do all the multiplication division etc and you should get your answers
anonymous
  • anonymous
OH!!!! Ok thank you thank you!! xD
anonymous
  • anonymous
I plugged the first numbers in and then i got 8.75 as my answer... but thats not on the options!
anonymous
  • anonymous
check your signs!!
anonymous
  • anonymous
i did!! thats why it took so long!
anonymous
  • anonymous
Ignore the rest, and look under the radical. Start 40^2, which is 1600. Then look at the rest of what is under the radical. Do -4x16x25. Do you get -1600? So the square root of 1600-1600 is 0.
anonymous
  • anonymous
Are we good to there?
anonymous
  • anonymous
yea i got that
anonymous
  • anonymous
but i didnt get the 1600 part for the first part i accidentally
anonymous
  • anonymous
put 4 because i squared the 40 then wasnt thinking and then i got the square root which was.. 40
anonymous
  • anonymous
so then would you do -40 + 32 ?
anonymous
  • anonymous
wait no im confused
anonymous
  • anonymous
Well remember, 2x16 is 32, but your not adding, you are dividing.
anonymous
  • anonymous
So You would have -40 plus the square root of all that junk that turned out to be zero.
anonymous
  • anonymous
-40/32 is -1.25
anonymous
  • anonymous
ohhhhh so u dont add?
anonymous
  • anonymous
wow ok thx i didnt even see that!!!
anonymous
  • anonymous
No. At the end, you set your equation OVER 2a. In other words, divide it by 2a.
anonymous
  • anonymous
ohhhhh ok?
anonymous
  • anonymous
http://www.regentsprep.org/Regents/math/algtrig/ATE3/quadsongs.htm memorize the equation, if you're in Algerbra or Algerbra 2 you're gonna use it again!
anonymous
  • anonymous
algebra*
anonymous
  • anonymous
ok thx!!! ya im in Algebra IIthe only reason im bad is because of all the confusing steps!!!! :P but thx u helped me ALOT!!!
anonymous
  • anonymous
No problem.
anonymous
  • anonymous
What a pun
anonymous
  • anonymous
wait wait so i wrote the problem down like this: x = (-b + - Square root of… B^2 – 4ac /2a
anonymous
  • anonymous
and then were we doing b^2 - 4ac or somethin?
anonymous
  • anonymous
bc i didnt understand why i would divide by 2a again which was 32
anonymous
  • anonymous
wait ok im confused UGH! i thought i got it!!!

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