Determine an equation of the line through the given point is parallel to the given line: (-1,2): 3y+2x=6

- anonymous

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- anonymous

What's the slope of the given line?

- anonymous

not sure

- anonymous

Can you quickly solve for y?

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## More answers

- anonymous

3y=6+2x

- anonymous

If you put the equation in the form y=mx + b m will be your slope.

- anonymous

err
y=mx+b
m is the slope.

- anonymous

That's not quite right. It should be
3y=-2x + 6

- anonymous

Now divide by 3.

- anonymous

So y=-2x+2

- anonymous

So y=-2x+2

- anonymous

No.
\[y=\frac{-2}{3}x + 2\]

- anonymous

Go a little slower, you 're making a number of clerical mistakes.

- anonymous

Okay, I understand. Now, isn't there yet another formula to put in the points?

- anonymous

Once you have the slope of the given line you know the slope of your parallel line (parallel lines have the same slope). You can make your new line using the point slope formula:
\[y-y_0 = m(x-x_0)\]
Where m is the slope of your line, and \(x_0,y_0\) are the x and y values of a point on the line.

- anonymous

So m=the -2/3+2

- anonymous

Sorry, i'm horrible at this

- anonymous

y-2=m(x-(-1))

- anonymous

Then y-2=m(x+1)

- anonymous

m = -2/3 Not the +2.

- anonymous

-2/3 is the slope.
y = mx + b
The m is the slope.

- anonymous

So is this right then.....y=-2/3s11

- anonymous

y-2=-2/3(x+1) is correct. Then simplify. into y = something.

- anonymous

Wow, i don't know how else to simplify this

- anonymous

\[y-2 = \frac{-2}{3}(x+1)\]
Add 2 to both sides.
\[y = \frac{-2}{3}(x+1) + 2 \]
Multiply through the -2/3.
\[y = \frac{-2}{3}x -\frac{2}{3} + 2 \]
Combine the non-variable terms.

- anonymous

So y=2?

- anonymous

Okay, i'm seriously horrible at this.

- anonymous

Is there a Algebra for Dummies book out there? I'm sure there is, and it's going to be with my other books.

- anonymous

There's a number of good videos you can watch.

- anonymous

http://www.khanacademy.org/video/simple-equations?playlist=Algebra

- anonymous

Start there and work on some of the more complicated equations too

- anonymous

Well, I need it seriously to finish this class. . Can you help me finish this one please.....

- anonymous

I will certainly do that.

- anonymous

Just bookmarked it.

- anonymous

You should have y = (-2/3)x + 4/3

- anonymous

All the other questions are coming up similar to 3x+y-6=0
They all have 0's at the ends..

- anonymous

That doesn't matter. You can always move things back and forth across the equal sign by adding or subtracting things.

- anonymous

So I could do -2/3x+y+2=0

- anonymous

You can, but there's no need.

- anonymous

thank you very much

- anonymous

Also that would be wrong.

- anonymous

Because you have to add (2/3)x -4/3 to both sides (or subtract y from both sides) to get 0.

- anonymous

Okay, i understand that. Thanks.

- anonymous

You sure are good at this.

- anonymous

You need to review working with equations a bit, and take things slowly, but you'll get there. Math is a practiced skill, not an innate talent.

- anonymous

I know, thanks again.

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