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anonymous
 5 years ago
quick clarification on quadratic equation
anonymous
 5 years ago
quick clarification on quadratic equation

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[16y ^{2}=24y+9\] my ? is, would a=16, b=24, and c=9?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or is it scrambled up so it's not in order?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I mean no thats wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Before doing quadratic equations, you always have to set them equal to zero. So you would have to add 16y^2 to the other side.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just need to know what a b and c are

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So your a is positive 16.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Your b and c stay the same.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you have to set up your equation to zero you can set however you want it as long as it equals zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thanks. Now I need to solve it. Will I have 2 non real answers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0woops i got it wrong \[ay^2 + by + c = 0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope you should get two real numbers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thanks. I'm gonna try and work it out. can someone let me know if this is right once I get it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[24+ or  \sqrt{576576}\over 32\] I got to this step and I'm assuming the 576 cancels, but idk exactly what to do with the other numbers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, they cancel, and the square root of 0 is 0. So for +: 24+0=24. Then divide it by 32, to get .75 or 3/4. And for : 240=24. Then divide it by 32 to get .75, or 3/4.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hold up, caught an error. When you get your final equation, you divide it by 2a. Look at your last post. You divided by 32. Our a=16. Not negative 16. So 2a= positive 32.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thanks for catching that. I'm wondering how I should type the 2 answers. it's an online assignment and it's picky with the correct format, so what exactly would it look like?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is is 24+ 3 over 4, and 24  3 over 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and my other ? is if there is a square root involved in the answer at all? or if that cancled out completely? Thanks for your help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0drats.. I guess i'm not sure what my answer should look like exactly

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This particular equation has only one answer, 3/4, because the square root turns out to be 0. If they are picky, you could write that the two final steps were (24+0)/32, and (240)/32, but because we are dealing with zeroes, they both have the same answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0someone else said there would be 2 solutions, and i think because it was squared it is supposed to have 2. Thanks, i'll try that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no square root sign i supose?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it wont let me do the 0 over a fraction. hm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, typically this equation would have two answers, because before every square root symbol is a "plusorminus" \[\pm\] sign. In this case, under the radical is zero. So there is only one solution.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you were right. I typed it in wrong though. Thanks so much! I have another one that i am not sure how to finish it off. Would you mind helping me with this one? Or should I post the question for someone else? :)
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