anonymous
  • anonymous
quick clarification on quadratic equation
Mathematics
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anonymous
  • anonymous
quick clarification on quadratic equation
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[-16y ^{2}=24y+9\] my ? is, would a=-16, b=24, and c=9?
anonymous
  • anonymous
or is it scrambled up so it's not in order?
anonymous
  • anonymous
it can

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anonymous
  • anonymous
I mean no thats wrong
anonymous
  • anonymous
Before doing quadratic equations, you always have to set them equal to zero. So you would have to add 16y^2 to the other side.
anonymous
  • anonymous
i just need to know what a b and c are
anonymous
  • anonymous
So your a is positive 16.
anonymous
  • anonymous
Your b and c stay the same.
anonymous
  • anonymous
\[ay^2+cy +c =0\]
anonymous
  • anonymous
so you have to set up your equation to zero you can set however you want it as long as it equals zero.
anonymous
  • anonymous
ok thanks. Now I need to solve it. Will I have 2 non real answers?
anonymous
  • anonymous
woops i got it wrong \[ay^2 + by + c = 0\]
anonymous
  • anonymous
nope you should get two real numbers.
anonymous
  • anonymous
ok thanks. I'm gonna try and work it out. can someone let me know if this is right once I get it
anonymous
  • anonymous
most definitley
anonymous
  • anonymous
definitely **
anonymous
  • anonymous
\[-24+ or - \sqrt{576-576}\over -32\] I got to this step and I'm assuming the 576 cancels, but idk exactly what to do with the other numbers?
anonymous
  • anonymous
Yes, they cancel, and the square root of 0 is 0. So for +: -24+0=-24. Then divide it by -32, to get .75 or 3/4. And for -: -24-0=-24. Then divide it by -32 to get .75, or 3/4.
anonymous
  • anonymous
Hold up, caught an error. When you get your final equation, you divide it by 2a. Look at your last post. You divided by -32. Our a=16. Not negative 16. So 2a= positive 32.
anonymous
  • anonymous
ok thanks for catching that. I'm wondering how I should type the 2 answers. it's an online assignment and it's picky with the correct format, so what exactly would it look like?
anonymous
  • anonymous
is is -24+ 3 over 4, and -24 - 3 over 4?
anonymous
  • anonymous
neither..
anonymous
  • anonymous
and my other ? is if there is a square root involved in the answer at all? or if that cancled out completely? Thanks for your help
anonymous
  • anonymous
drats.. I guess i'm not sure what my answer should look like exactly
anonymous
  • anonymous
This particular equation has only one answer, 3/4, because the square root turns out to be 0. If they are picky, you could write that the two final steps were (-24+0)/32, and (-24-0)/32, but because we are dealing with zeroes, they both have the same answer.
anonymous
  • anonymous
someone else said there would be 2 solutions, and i think because it was squared it is supposed to have 2. Thanks, i'll try that
anonymous
  • anonymous
no square root sign i supose?
anonymous
  • anonymous
it wont let me do the 0 over a fraction. hm
anonymous
  • anonymous
Yes, typically this equation would have two answers, because before every square root symbol is a "plus-or-minus" \[\pm\] sign. In this case, under the radical is zero. So there is only one solution.
anonymous
  • anonymous
you were right. I typed it in wrong though. Thanks so much! I have another one that i am not sure how to finish it off. Would you mind helping me with this one? Or should I post the question for someone else? :)

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