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anonymous

  • 5 years ago

quick clarification on quadratic equation

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  1. anonymous
    • 5 years ago
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    \[-16y ^{2}=24y+9\] my ? is, would a=-16, b=24, and c=9?

  2. anonymous
    • 5 years ago
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    or is it scrambled up so it's not in order?

  3. anonymous
    • 5 years ago
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    it can

  4. anonymous
    • 5 years ago
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    I mean no thats wrong

  5. anonymous
    • 5 years ago
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    Before doing quadratic equations, you always have to set them equal to zero. So you would have to add 16y^2 to the other side.

  6. anonymous
    • 5 years ago
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    i just need to know what a b and c are

  7. anonymous
    • 5 years ago
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    So your a is positive 16.

  8. anonymous
    • 5 years ago
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    Your b and c stay the same.

  9. anonymous
    • 5 years ago
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    \[ay^2+cy +c =0\]

  10. anonymous
    • 5 years ago
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    so you have to set up your equation to zero you can set however you want it as long as it equals zero.

  11. anonymous
    • 5 years ago
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    ok thanks. Now I need to solve it. Will I have 2 non real answers?

  12. anonymous
    • 5 years ago
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    woops i got it wrong \[ay^2 + by + c = 0\]

  13. anonymous
    • 5 years ago
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    nope you should get two real numbers.

  14. anonymous
    • 5 years ago
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    ok thanks. I'm gonna try and work it out. can someone let me know if this is right once I get it

  15. anonymous
    • 5 years ago
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    most definitley

  16. anonymous
    • 5 years ago
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    definitely **

  17. anonymous
    • 5 years ago
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    \[-24+ or - \sqrt{576-576}\over -32\] I got to this step and I'm assuming the 576 cancels, but idk exactly what to do with the other numbers?

  18. anonymous
    • 5 years ago
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    Yes, they cancel, and the square root of 0 is 0. So for +: -24+0=-24. Then divide it by -32, to get .75 or 3/4. And for -: -24-0=-24. Then divide it by -32 to get .75, or 3/4.

  19. anonymous
    • 5 years ago
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    Hold up, caught an error. When you get your final equation, you divide it by 2a. Look at your last post. You divided by -32. Our a=16. Not negative 16. So 2a= positive 32.

  20. anonymous
    • 5 years ago
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    ok thanks for catching that. I'm wondering how I should type the 2 answers. it's an online assignment and it's picky with the correct format, so what exactly would it look like?

  21. anonymous
    • 5 years ago
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    is is -24+ 3 over 4, and -24 - 3 over 4?

  22. anonymous
    • 5 years ago
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    neither..

  23. anonymous
    • 5 years ago
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    and my other ? is if there is a square root involved in the answer at all? or if that cancled out completely? Thanks for your help

  24. anonymous
    • 5 years ago
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    drats.. I guess i'm not sure what my answer should look like exactly

  25. anonymous
    • 5 years ago
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    This particular equation has only one answer, 3/4, because the square root turns out to be 0. If they are picky, you could write that the two final steps were (-24+0)/32, and (-24-0)/32, but because we are dealing with zeroes, they both have the same answer.

  26. anonymous
    • 5 years ago
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    someone else said there would be 2 solutions, and i think because it was squared it is supposed to have 2. Thanks, i'll try that

  27. anonymous
    • 5 years ago
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    no square root sign i supose?

  28. anonymous
    • 5 years ago
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    it wont let me do the 0 over a fraction. hm

  29. anonymous
    • 5 years ago
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    Yes, typically this equation would have two answers, because before every square root symbol is a "plus-or-minus" \[\pm\] sign. In this case, under the radical is zero. So there is only one solution.

  30. anonymous
    • 5 years ago
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    you were right. I typed it in wrong though. Thanks so much! I have another one that i am not sure how to finish it off. Would you mind helping me with this one? Or should I post the question for someone else? :)

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