anonymous
  • anonymous
Cylinder with cone removed
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
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amistre64
  • amistre64
you want the volume left after cone is removed?
amistre64
  • amistre64
Vcylinder = Base area x height Vcone = (1/3) Vcyl Vleft over = 2/3 Vcyl

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More answers

anonymous
  • anonymous
i need that vcylinder-vcone
amistre64
  • amistre64
Base area = pi r^2 = 36pi Vleft = 2(12)pi = 24pi
amistre64
  • amistre64
thats wrong, i missed a step lol
amistre64
  • amistre64
(16)24pi = 384pi (2)384pi ------- = 256pi = about 803.84 3
amistre64
  • amistre64
i see my mistake again lol
anonymous
  • anonymous
so i have to subtract 384 and 256
amistre64
  • amistre64
1 - 1/3 = 2/3...... let me redo that, I used a wrong number.
amistre64
  • amistre64
Base area = pi r^2 = 36pi 16(36pi) = 576pi is the area of the cylinder (2)576pi ------- = 384pi =about 1205.76 3
anonymous
  • anonymous
then subtract it right
amistre64
  • amistre64
576pi is the volume of the container; the volume of the cone is just a third so what we have left over is 2 thirds of the volume when the cone is removed. whats left is 384pi , which is about 1205.76 and that is the answer. No subtracting nothing from anything :)
anonymous
  • anonymous
umm ok thank and can u help me with the other problem
amistre64
  • amistre64
which one...
anonymous
  • anonymous
find the title that said cone

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