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anonymous

  • 5 years ago

Cylinder with cone removed

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  1. anonymous
    • 5 years ago
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  2. amistre64
    • 5 years ago
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    you want the volume left after cone is removed?

  3. amistre64
    • 5 years ago
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    Vcylinder = Base area x height Vcone = (1/3) Vcyl Vleft over = 2/3 Vcyl

  4. anonymous
    • 5 years ago
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    i need that vcylinder-vcone

  5. amistre64
    • 5 years ago
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    Base area = pi r^2 = 36pi Vleft = 2(12)pi = 24pi

  6. amistre64
    • 5 years ago
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    thats wrong, i missed a step lol

  7. amistre64
    • 5 years ago
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    (16)24pi = 384pi (2)384pi ------- = 256pi = about 803.84 3

  8. amistre64
    • 5 years ago
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    i see my mistake again lol

  9. anonymous
    • 5 years ago
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    so i have to subtract 384 and 256

  10. amistre64
    • 5 years ago
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    1 - 1/3 = 2/3...... let me redo that, I used a wrong number.

  11. amistre64
    • 5 years ago
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    Base area = pi r^2 = 36pi 16(36pi) = 576pi is the area of the cylinder (2)576pi ------- = 384pi =about 1205.76 3

  12. anonymous
    • 5 years ago
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    then subtract it right

  13. amistre64
    • 5 years ago
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    576pi is the volume of the container; the volume of the cone is just a third so what we have left over is 2 thirds of the volume when the cone is removed. whats left is 384pi , which is about 1205.76 and that is the answer. No subtracting nothing from anything :)

  14. anonymous
    • 5 years ago
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    umm ok thank and can u help me with the other problem

  15. amistre64
    • 5 years ago
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    which one...

  16. anonymous
    • 5 years ago
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    find the title that said cone

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