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anonymous

  • 5 years ago

Find the standard form of the equation of the line that passes through the points (-1,-1) and (3,4)

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  1. anonymous
    • 5 years ago
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    Did you find the slope of the line?

  2. anonymous
    • 5 years ago
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    no

  3. anonymous
    • 5 years ago
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    Do you know the formula for the slope?

  4. anonymous
    • 5 years ago
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    x1-y2 X2 -Y2 ?

  5. anonymous
    • 5 years ago
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    y1

  6. anonymous
    • 5 years ago
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    Not quite. \[Slope =\frac{\text{Change in y}}{\text{Change in x}} = \frac{y_2-y_1}{x_2-x_1}\]

  7. anonymous
    • 5 years ago
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    so the slope is 3/5?

  8. anonymous
    • 5 years ago
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    5/4

  9. anonymous
    • 5 years ago
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    \[\frac{4-(-1)}{3-(-1)}\]

  10. anonymous
    • 5 years ago
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    so then what is my standard form equation?

  11. anonymous
    • 5 years ago
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    Once you have the slope, you can plug that into the point slope formula. \[y-y_1 = M(x-x_1)\] Where M is the slope.

  12. anonymous
    • 5 years ago
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    And \(x_1,y_1\) are the x and y values of a point on the line (you can pick either point for this)

  13. anonymous
    • 5 years ago
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    i give up

  14. anonymous
    • 5 years ago
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    Why? You were doing fine so far.

  15. anonymous
    • 5 years ago
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    You found M = 5/4

  16. anonymous
    • 5 years ago
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    You are given the x and y values for 2 points, just pick one and plug them in.

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