Find the standard form of the equation of the line that passes through the points (-1,-1) and (3,4)

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Find the standard form of the equation of the line that passes through the points (-1,-1) and (3,4)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Did you find the slope of the line?
no
Do you know the formula for the slope?

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Other answers:

x1-y2 X2 -Y2 ?
y1
Not quite. \[Slope =\frac{\text{Change in y}}{\text{Change in x}} = \frac{y_2-y_1}{x_2-x_1}\]
so the slope is 3/5?
5/4
\[\frac{4-(-1)}{3-(-1)}\]
so then what is my standard form equation?
Once you have the slope, you can plug that into the point slope formula. \[y-y_1 = M(x-x_1)\] Where M is the slope.
And \(x_1,y_1\) are the x and y values of a point on the line (you can pick either point for this)
i give up
Why? You were doing fine so far.
You found M = 5/4
You are given the x and y values for 2 points, just pick one and plug them in.

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