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anonymous

  • 5 years ago

find the absolute and local maximum and minimum values of f.f(x) = 8 - 2x x ≥ 1

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  1. anonymous
    • 5 years ago
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    Is this calculus? Or algebra 2?

  2. anonymous
    • 5 years ago
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    Find all critical points and plug them in to the function and the highest number is the absolute max and lowest is the absolute min. Dont forget to include 1 since that's one bound.

  3. anonymous
    • 5 years ago
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    how do i find the criteria

  4. anonymous
    • 5 years ago
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    Are you taking algebra, or calculus?

  5. anonymous
    • 5 years ago
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    Because there are a few ways to do this depending on what you know.

  6. anonymous
    • 5 years ago
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    calculus

  7. anonymous
    • 5 years ago
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    Ok, so take the derivative of f. What do you have?

  8. anonymous
    • 5 years ago
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    -2

  9. anonymous
    • 5 years ago
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    Right. So when you are finding local mins/maxes you are looking for places where the derivative is 0. When is -2=0?

  10. anonymous
    • 5 years ago
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    never lol

  11. anonymous
    • 5 years ago
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    So there are no local mins or maxes. So you just have to look at the value at the "end" points for absolute mins/maxes. Which is to say x=1, there is no other end point because the other bound goes to \(\infty\)

  12. anonymous
    • 5 years ago
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    So what is the value at x=1?

  13. anonymous
    • 5 years ago
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    6

  14. anonymous
    • 5 years ago
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    And what happens as x gets larger? Is f(1)=6 an absolute min or is it a max?

  15. anonymous
    • 5 years ago
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    max

  16. anonymous
    • 5 years ago
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    so 6 is the max

  17. anonymous
    • 5 years ago
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    Yes. And it has no absolute min, and no local mins or maxes.

  18. anonymous
    • 5 years ago
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    ok i get it!!!

  19. anonymous
    • 5 years ago
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    thank u!

  20. anonymous
    • 5 years ago
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    Of course!

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