anonymous
  • anonymous
Will someone please help me.. I don't know what i did wrong with a couple of problems please help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I'll help with one.
anonymous
  • anonymous
okay it says to find the volume of the solid
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anonymous
  • anonymous
Do you know the formula for the volume of a cone?

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anonymous
  • anonymous
not of the top of my head
anonymous
  • anonymous
sorry, my computer just froze up it is (1/3)*Pi*r^2*h
anonymous
  • anonymous
are 10 and 18 the heights, or are they the length of the lines they are next to?
anonymous
  • anonymous
yes so \[1/3\times \pi \times 5^{2}\times10\]
anonymous
  • anonymous
only if 10 is the height
anonymous
  • anonymous
\[1/3\times \pi \times 5^{2}\times18\]
anonymous
  • anonymous
10 is the height of the top cone and 18 is the height of the bottom cone
anonymous
  • anonymous
Actually, I don't think so. If you do it that way you get 733.04, which got counted wrong on your test.
anonymous
  • anonymous
I doubt you would get it wrong for being off by .04
anonymous
  • anonymous
So, lets assume that 18 and 10 are the lengths of the lines they are next to, and not the heights.
anonymous
  • anonymous
You following so far?
anonymous
  • anonymous
yea
anonymous
  • anonymous
Awesome. We need the heights to use our formula, so now we just need to figure out how to get them. Thinking in 3D is rather tricky, so I like to make this into something I can do in 2D.
anonymous
  • anonymous
Notice how we have the radius and the hypotenuse of a right triangle?
anonymous
  • anonymous
ya
anonymous
  • anonymous
Well, we can use the good old Pythagorean formula to figure out the missing side.
anonymous
  • anonymous
Sqrt[18^2-5^2] and Sqrt[10^2-5^2] are our two heights
anonymous
  • anonymous
(1/3)Pi*( Sqrt[18^2-5^2] )^2 + (1/3)Pi*( Sqrt[10^2-5^2] )^2
anonymous
  • anonymous
^ That should give you the correct answer, which comes out to be...
anonymous
  • anonymous
idk i dont have a calculator
anonymous
  • anonymous
oops, I did that formula wrong :/
anonymous
  • anonymous
(1/3)Pi*( Sqrt[18^2-5^2] )^2 + (1/3)Pi*( Sqrt[10^2-5^2] )^2 isn't right, but you get the idea
anonymous
  • anonymous
I left out the radius
anonymous
  • anonymous
You get it though, right?
anonymous
  • anonymous
kinda
anonymous
  • anonymous
(1/3)*Pi*r^2*h
anonymous
  • anonymous
you did it right, if 10 and 18 had been the height. Unfortunatly, they were the side length (confusing problem)
anonymous
  • anonymous
you just use the Pythagorean formula to get the heights, and do the same thing with them that you did with 10 and 18 the first time around.
anonymous
  • anonymous
Well, I'm sleepy, so I'm off to bed. I have to wake up and do calculus D:

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