Will someone please help me.. I don't know what i did wrong with a couple of problems please help

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Will someone please help me.. I don't know what i did wrong with a couple of problems please help

Mathematics
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I'll help with one.
okay it says to find the volume of the solid
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Do you know the formula for the volume of a cone?

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not of the top of my head
sorry, my computer just froze up it is (1/3)*Pi*r^2*h
are 10 and 18 the heights, or are they the length of the lines they are next to?
yes so \[1/3\times \pi \times 5^{2}\times10\]
only if 10 is the height
\[1/3\times \pi \times 5^{2}\times18\]
10 is the height of the top cone and 18 is the height of the bottom cone
Actually, I don't think so. If you do it that way you get 733.04, which got counted wrong on your test.
I doubt you would get it wrong for being off by .04
So, lets assume that 18 and 10 are the lengths of the lines they are next to, and not the heights.
You following so far?
yea
Awesome. We need the heights to use our formula, so now we just need to figure out how to get them. Thinking in 3D is rather tricky, so I like to make this into something I can do in 2D.
Notice how we have the radius and the hypotenuse of a right triangle?
ya
Well, we can use the good old Pythagorean formula to figure out the missing side.
Sqrt[18^2-5^2] and Sqrt[10^2-5^2] are our two heights
(1/3)Pi*( Sqrt[18^2-5^2] )^2 + (1/3)Pi*( Sqrt[10^2-5^2] )^2
^ That should give you the correct answer, which comes out to be...
idk i dont have a calculator
oops, I did that formula wrong :/
(1/3)Pi*( Sqrt[18^2-5^2] )^2 + (1/3)Pi*( Sqrt[10^2-5^2] )^2 isn't right, but you get the idea
I left out the radius
You get it though, right?
kinda
(1/3)*Pi*r^2*h
you did it right, if 10 and 18 had been the height. Unfortunatly, they were the side length (confusing problem)
you just use the Pythagorean formula to get the heights, and do the same thing with them that you did with 10 and 18 the first time around.
Well, I'm sleepy, so I'm off to bed. I have to wake up and do calculus D:

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