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anonymous
 5 years ago
Will someone please help me.. I don't know what i did wrong with a couple of problems please help
anonymous
 5 years ago
Will someone please help me.. I don't know what i did wrong with a couple of problems please help

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay it says to find the volume of the solid

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know the formula for the volume of a cone?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not of the top of my head

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, my computer just froze up it is (1/3)*Pi*r^2*h

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are 10 and 18 the heights, or are they the length of the lines they are next to?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes so \[1/3\times \pi \times 5^{2}\times10\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0only if 10 is the height

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1/3\times \pi \times 5^{2}\times18\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.010 is the height of the top cone and 18 is the height of the bottom cone

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Actually, I don't think so. If you do it that way you get 733.04, which got counted wrong on your test.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I doubt you would get it wrong for being off by .04

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, lets assume that 18 and 10 are the lengths of the lines they are next to, and not the heights.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You following so far?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Awesome. We need the heights to use our formula, so now we just need to figure out how to get them. Thinking in 3D is rather tricky, so I like to make this into something I can do in 2D.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Notice how we have the radius and the hypotenuse of a right triangle?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, we can use the good old Pythagorean formula to figure out the missing side.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sqrt[18^25^2] and Sqrt[10^25^2] are our two heights

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(1/3)Pi*( Sqrt[18^25^2] )^2 + (1/3)Pi*( Sqrt[10^25^2] )^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0^ That should give you the correct answer, which comes out to be...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0idk i dont have a calculator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops, I did that formula wrong :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(1/3)Pi*( Sqrt[18^25^2] )^2 + (1/3)Pi*( Sqrt[10^25^2] )^2 isn't right, but you get the idea

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I left out the radius

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You get it though, right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you did it right, if 10 and 18 had been the height. Unfortunatly, they were the side length (confusing problem)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you just use the Pythagorean formula to get the heights, and do the same thing with them that you did with 10 and 18 the first time around.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, I'm sleepy, so I'm off to bed. I have to wake up and do calculus D:
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