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anonymous
 5 years ago
need help finishing up this quadratic equation!
anonymous
 5 years ago
need help finishing up this quadratic equation!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am at \[4 + or  \sqrt{40} \over 14\] Any one able to help me with where to go from here? and whether this is correct or not?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it doesn't look right since you suppose to have a real number. Can you please show us the original function.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I checked it and it's right. The only thing I can see to do is that radical... It would come out as 2 times the root of ten.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would the 2 and 10 be positive or negative?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, 2i times the root of ten (:

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okk awesome. Thanks. is the denominator positive 14 then? so my 2 answers would be, \[4+ or  \sqrt{2i} over 14\] and the second answer would be the same, except root 10 instead of 2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, I just am not sure exactly what the answer should look like, i have to answer it in an online assignment and i wanna make sure to get the right format

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[4 + or  2i \sqrt{10}\over 14\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry it took so long. But this counts as two answers since it's + or  as well.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and are they non real?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since theres a negative number i assume so

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm not quite sure but i'd say since there's an imaginary number in there, it's nonreal.
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