anonymous
  • anonymous
I need someone to just check my work... and tell me where I went wrong?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
The problem is 2^x+3=5x
anonymous
  • anonymous
What did you get?
anonymous
  • anonymous
next step: (x+3)ln2/xln2=xln5/xln2

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More answers

anonymous
  • anonymous
I got 2.269
anonymous
  • anonymous
next step: x+3/x=ln5/ln2
anonymous
  • anonymous
next step: x+3/x=2.322/1
anonymous
  • anonymous
Something is wrong. Was the original equation \[2^{x+3} = 5^x\] ?
anonymous
  • anonymous
no 2^ x+3=5x
anonymous
  • anonymous
Ok, then when you take the ln of both sides you'll have ln5 + lnx on the right hand side of the equal.
anonymous
  • anonymous
Which is gonna be a pain.
anonymous
  • anonymous
Was it \[2^{x+3} = 5x\] ?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
Yeah, there's no good way to simplify that. I suspect you have the question wrong.
anonymous
  • anonymous
Best you can do is something like \[x(ln 2) - lnx = ln(5/3)\]
anonymous
  • anonymous
Err wait, that should be ln(5/8) on the right side.
anonymous
  • anonymous
My teacher told us to set each side to the natural... which gave me: (x+3)ln2=xln5
anonymous
  • anonymous
Then I needed to get everything canceled out by cross multiplying... so I divided both sides by xln2
anonymous
  • anonymous
That's not right though. Unless you had 5^x on the right side originally.
anonymous
  • anonymous
Was it \(5x\) or \(5^x\)
anonymous
  • anonymous
the second one... I just looked in my book. Im so sorry
anonymous
  • anonymous
Ok good.
anonymous
  • anonymous
So yeah that's right. take the ln of both sides (or any log really)
anonymous
  • anonymous
Then solve for x. Don't plug anything into your calculator until you have something where x = something that has no x
anonymous
  • anonymous
(x+3)ln2=xln5 is correct for starting out
anonymous
  • anonymous
ok... then what do I need to divide both sides by? she taught us to cross multiply? I divided both sides by xln2 just to cancel out. And I ended up with x+3/x=ln5/ln2
anonymous
  • anonymous
Get all terms with an x on one side.
anonymous
  • anonymous
Or that. Cross multiplying works fine
anonymous
  • anonymous
I usually multiply out products, but you don't need to here
anonymous
  • anonymous
Just be sure that you do (x+3)/x = ln5/ln2
anonymous
  • anonymous
Not just the 3.
anonymous
  • anonymous
I did and I got: x+3/x= 2.322/1
anonymous
  • anonymous
then: x+3=2.322x
anonymous
  • anonymous
Don't plug things in.
anonymous
  • anonymous
Keep solving the equation until you have x by itself. x = something that has no x.
anonymous
  • anonymous
Then plug in
anonymous
  • anonymous
Im not sure what/where.I am attempting to get x by itself? I thought that is what I was doing?
anonymous
  • anonymous
I think cross multiplying is just making this harder.
anonymous
  • anonymous
I just got a different answer of -4.425
anonymous
  • anonymous
Lets back up.
anonymous
  • anonymous
Ok..Im just trying to follow the instructions. But Im willing to try anything at this point
anonymous
  • anonymous
\[(x+3)ln2=xln5\] \[x(ln2)+3(ln2)=x(ln5)\] \[x(ln2)- x(ln5)= - 3(ln2)\] \[x[(ln2)- (ln5)]= - 3(ln2)\] \[x= \frac{- 3(ln2)}{(ln2)- (ln5)}\]
anonymous
  • anonymous
Thanks for your time.. I appreciate it. I will continue to search for the answer. I need to learn it the way she taught us, Im afraid I will be jumping the gun and not learning anything... thanks so much.

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