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The problem is
2^x+3=5x

What did you get?

next step:
(x+3)ln2/xln2=xln5/xln2

I got 2.269

next step:
x+3/x=ln5/ln2

next step:
x+3/x=2.322/1

Something is wrong. Was the original equation
\[2^{x+3} = 5^x\]
?

no 2^ x+3=5x

Which is gonna be a pain.

Was it \[2^{x+3} = 5x\] ?

Yes

Yeah, there's no good way to simplify that. I suspect you have the question wrong.

Best you can do is something like
\[x(ln 2) - lnx = ln(5/3)\]

Err wait, that should be ln(5/8) on the right side.

My teacher told us to set each side to the natural...
which gave me:
(x+3)ln2=xln5

Then I needed to get everything canceled out by cross multiplying... so I divided both sides by xln2

That's not right though. Unless you had 5^x on the right side originally.

Was it \(5x\) or \(5^x\)

the second one... I just looked in my book. Im so sorry

Ok good.

So yeah that's right. take the ln of both sides (or any log really)

(x+3)ln2=xln5
is correct for starting out

Get all terms with an x on one side.

Or that. Cross multiplying works fine

I usually multiply out products, but you don't need to here

Just be sure that you do (x+3)/x = ln5/ln2

Not just the 3.

I did and I got:
x+3/x= 2.322/1

then:
x+3=2.322x

Don't plug things in.

Keep solving the equation until you have x by itself.
x = something that has no x.

Then plug in

Im not sure what/where.I am attempting to get x by itself? I thought that is what I was doing?

I think cross multiplying is just making this harder.

I just got a different answer of -4.425

Lets back up.

Ok..Im just trying to follow the instructions. But Im willing to try anything at this point