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anonymous
 5 years ago
can anyone help out with power series?
anonymous
 5 years ago
can anyone help out with power series?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so waht is your question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find the radius of convergence and the interval of convergence of the power series. the sum from n=0 to infinity of 2^n x^n / n!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i used ratio test and found it converges absolutely, but im not sure how to find the Radius on convergence or interval

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you mind giving me the last few lines of your ratio test?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well it boiled down to lim=2x/n+1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so limn>inifinity, 2x/(n+1) > 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that mean the interval is (infin, infin) and radius of convergence is infinity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, just so i understand though what is the R value

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so how was i able to decipher that the R value is infinity just from knowing the series converged absolutely?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i guess im asking why does geting L=0 from the ratio test help me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u can interpret it this way lim n>infin x(2/(n+1))<1 , then x<1/ 0 x<infinity=R

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0X is a constant. So no mater what X is, the limit will go to 0, and the ratio test states that if the limit is <1, it converges. So X can be any real numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah ok, so becasue this series converges no matter what xvalue is plugged in: my x value can range from infinity to +infinity bc it will always converge. and then the radius for that interval is infinity also

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thankyou very much i appreciate it. and just for learning purposes, do i know this series is centered at 0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and that is bc the xa isnt there?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Becasue it is the form of c0+c1(x)+c2(x)^2 +....cn(x)^n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so its in the c0 form

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea cn(x)^n then it is centered at 0, if it is cn(x1)^n then it would be centered at x=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and in my equation here the 2^2/n! is the Cn part

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right right ok im dumb

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOL no i know that is you meant.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well i really do appreciate this. It may not seem it but you just helped someone who will most likely be getting early admission to UB med school ha ha Ive been getting pounded with organic and inorganic so this has been on the back burner

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOL my pleasure and honor :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0keep up the good work you are really patient, and a good listener. Guys like you are doing it for the love of the game if you will.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOL alright if u have any further questions, just post here :) i am gonna go now Bye :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh can you find the radius of convergence for this power series : sum n = 0 to n =infinity ((x+3)^n)/(e^3n!)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0welp i think the ratio test gives you the limit to approach zero again, so i guess its infinity again?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks lol i was arguing with my friend about the convergence of this series.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah like at the end of my ratio test i got x+3 ontop

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the numerator is like e^3n+1 time e^3n+2 times e^3m+3 so thats infinity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just meant denominator* sorry so basicall that makes the denom infinity and the numerator x+3
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