anonymous
  • anonymous
clarification on the answer for this quadratic equation!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[-4x ^{2}-x=-2\]
anonymous
  • anonymous
right now I have \[x=1+ or - \sqrt{-31}\over -8\] I don't know if there can be any more done
anonymous
  • anonymous
I never know when exactly the i's come into play..

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More answers

amistre64
  • amistre64
4x^2 +x -2 = 0 -1/8 +- sqrt(33)/8 should be the answer
amistre64
  • amistre64
put everything on the side that makes the x^2 part positive...
anonymous
  • anonymous
so there are 2 non real answers?
amistre64
  • amistre64
0 = 4x^2 +x -2 is alot easier to play with :)
amistre64
  • amistre64
there are 2 real answers. why you get sqrt(-31)? thats wrong
amistre64
  • amistre64
sqrt(1-(4)(4)(-2)) = sqrt(33)
anonymous
  • anonymous
1-32 is how I got that.. 4 times a times c is what my format told me to do.. hmm. must have messed something up
amistre64
  • amistre64
get your quad to be a positive 4x^2..... you can put that stuff on either side of the equals sign to make life easier.
amistre64
  • amistre64
sqrt(1 -(4)(4)(-2)) = sqrt(1 + 32) = sqrt(33)
anonymous
  • anonymous
gotcha. I see where I messed up, thanks! Would you mind helping with this one once I work out the answer, just to make sure i'm doing it right?:)
amistre64
  • amistre64
not a problem
anonymous
  • anonymous
\[X ^{2}+10X+25=0\] Is the problem.
anonymous
  • anonymous
so far I have \[-10 + or - \sqrt{4}\over 2\] So i'm wondering if the 2 and 4 turn into 2 over 1...?
amistre64
  • amistre64
if we want to really work this with the quad formula then we should get: -10/2 +- sqrt(100 -(4)(25))/2 -10/2 +- sqrt(100-100)/2 <- thats zero -10/2 = -5
anonymous
  • anonymous
ohh i did 100-96 to get that. i wrote 24 instead of 25..My bad. So is there only 1 solution for this?
amistre64
  • amistre64
yes, only one solution. It touches the x axis in only one place....x = -5
anonymous
  • anonymous
thank you!
amistre64
  • amistre64
youre welcome :)
anonymous
  • anonymous
I have like 10 more of these so i'll probably keep posting them on here to make sure I get them right. So if you don't mind I will just stay on this window and show them to you, otherwise I can see if others want to help. It's up to you! I understand if you have better things to do :)
amistre64
  • amistre64
better things? no, but I might not be able to get to them, so post them in the left side so others can have a chance at them :)
anonymous
  • anonymous
Ok sounds good! Ha, thanks for your help :)

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