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  • 5 years ago

How do you solve for eigenvectors? I get the eigenvalues. Here is the problem. [2 0 0 1 -1 -2 -1 0 1] The characteristic polynomial is -x^3+2x^2+x-2 (obviously is lambda but I am using x for now) eigen values are x1= -1 x2= 1 x3= 2 How would you do the eigenvectors?

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  1. anonymous
    • 5 years ago
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    Replace your eigenvalues, one at a time, for lambda in your (A-xI) matrix- where x is lambda. So you'll have 3 separate matrix equations, (A-xI) v = 0, to solve for three different eigenvectors. You're almost there, just that one last step!

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