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anonymous

  • 5 years ago

Of this quadratic equation, does a=-2, b=3, and c=-4?

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  1. anonymous
    • 5 years ago
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    \[-2y ^{2}+3y=-4\]

  2. anonymous
    • 5 years ago
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    c = 4

  3. anonymous
    • 5 years ago
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    thanks!makes that become positive?

  4. anonymous
    • 5 years ago
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    -2y^2 + 3y +4 =0

  5. anonymous
    • 5 years ago
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    and would you mind if I try and solve it and post it on here so you can let me know if the answer I get is correct? :)

  6. anonymous
    • 5 years ago
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    ok

  7. anonymous
    • 5 years ago
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    \[-3 + or - \sqrt{41} \over -4\] is this my answer or is there more I can do with it? Also, would there be 2 real answers?

  8. anonymous
    • 5 years ago
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    or 2 non real solutions since there are negative numbers..

  9. anonymous
    • 5 years ago
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    D = b^2-4ac = 9-(4*-2*4) =9+32 = 41 >0 means 2 real answer u are correct

  10. anonymous
    • 5 years ago
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    okk thanks. I'm kind of confused though. Would the 2 answers be what I put? If so, wouldn't they not be real since there are negative numbers? Sorry. I guess to clarify could you post what the final 2 answers are? :)

  11. anonymous
    • 5 years ago
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    (-3 - sqrt(41))/-4 and (-3 + sqrt(41))/-4 not real or imaginary is if sqrt(-41) - sqrt(41) is real because negative sign is out of sqrt

  12. anonymous
    • 5 years ago
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    oohh ok. thanks!

  13. anonymous
    • 5 years ago
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    no problem

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