anonymous
  • anonymous
Give the domain for f(x,y) = ln(1-x^2 - y^2) How do you get this?
Mathematics
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anonymous
  • anonymous
Give the domain for f(x,y) = ln(1-x^2 - y^2) How do you get this?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
i think the domain is real
anonymous
  • anonymous
yeah i know the answer is -1<=x<1 and -1<=y<1 atleast i think, But I am unsure how to get to that
anonymous
  • anonymous
edit: yes thats the correct answer just checked with wolfram but still have no idea

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anonymous
  • anonymous
would you say 1-x^2 - y^2 >0 then try to solve i would suppose
anonymous
  • anonymous
if you do that you in the end you got circle domain
anonymous
  • anonymous
which would be the correct domain
anonymous
  • anonymous
i think u have to convert it to e, coz e is a constanta, it's easier to prove
anonymous
  • anonymous
okay I got it, Just had to play around with the inequality and the x and y but It came out correct. Thanks for the help!

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