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tdabboud
 4 years ago
Give the domain for f(x,y) = ln(1x^2  y^2)
How do you get this?
tdabboud
 4 years ago
Give the domain for f(x,y) = ln(1x^2  y^2) How do you get this?

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suzi20
 4 years ago
Best ResponseYou've already chosen the best response.0i think the domain is real

tdabboud
 4 years ago
Best ResponseYou've already chosen the best response.0yeah i know the answer is 1<=x<1 and 1<=y<1 atleast i think, But I am unsure how to get to that

tdabboud
 4 years ago
Best ResponseYou've already chosen the best response.0edit: yes thats the correct answer just checked with wolfram but still have no idea

tdabboud
 4 years ago
Best ResponseYou've already chosen the best response.0would you say 1x^2  y^2 >0 then try to solve i would suppose

suzi20
 4 years ago
Best ResponseYou've already chosen the best response.0if you do that you in the end you got circle domain

tdabboud
 4 years ago
Best ResponseYou've already chosen the best response.0which would be the correct domain

suzi20
 4 years ago
Best ResponseYou've already chosen the best response.0i think u have to convert it to e, coz e is a constanta, it's easier to prove

tdabboud
 4 years ago
Best ResponseYou've already chosen the best response.0okay I got it, Just had to play around with the inequality and the x and y but It came out correct. Thanks for the help!
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