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tdabboud

Give the domain for f(x,y) = ln(1-x^2 - y^2) How do you get this?

  • 3 years ago
  • 3 years ago

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  1. suzi20
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    i think the domain is real

    • 3 years ago
  2. tdabboud
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    yeah i know the answer is -1<=x<1 and -1<=y<1 atleast i think, But I am unsure how to get to that

    • 3 years ago
  3. tdabboud
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    edit: yes thats the correct answer just checked with wolfram but still have no idea

    • 3 years ago
  4. tdabboud
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    would you say 1-x^2 - y^2 >0 then try to solve i would suppose

    • 3 years ago
  5. suzi20
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    if you do that you in the end you got circle domain

    • 3 years ago
  6. tdabboud
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    which would be the correct domain

    • 3 years ago
  7. suzi20
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    i think u have to convert it to e, coz e is a constanta, it's easier to prove

    • 3 years ago
  8. tdabboud
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    okay I got it, Just had to play around with the inequality and the x and y but It came out correct. Thanks for the help!

    • 3 years ago
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