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tdabboud
Group Title
Give the domain for f(x,y) = ln(1x^2  y^2)
How do you get this?
 3 years ago
 3 years ago
tdabboud Group Title
Give the domain for f(x,y) = ln(1x^2  y^2) How do you get this?
 3 years ago
 3 years ago

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suzi20 Group TitleBest ResponseYou've already chosen the best response.0
i think the domain is real
 3 years ago

tdabboud Group TitleBest ResponseYou've already chosen the best response.0
yeah i know the answer is 1<=x<1 and 1<=y<1 atleast i think, But I am unsure how to get to that
 3 years ago

tdabboud Group TitleBest ResponseYou've already chosen the best response.0
edit: yes thats the correct answer just checked with wolfram but still have no idea
 3 years ago

tdabboud Group TitleBest ResponseYou've already chosen the best response.0
would you say 1x^2  y^2 >0 then try to solve i would suppose
 3 years ago

suzi20 Group TitleBest ResponseYou've already chosen the best response.0
if you do that you in the end you got circle domain
 3 years ago

tdabboud Group TitleBest ResponseYou've already chosen the best response.0
which would be the correct domain
 3 years ago

suzi20 Group TitleBest ResponseYou've already chosen the best response.0
i think u have to convert it to e, coz e is a constanta, it's easier to prove
 3 years ago

tdabboud Group TitleBest ResponseYou've already chosen the best response.0
okay I got it, Just had to play around with the inequality and the x and y but It came out correct. Thanks for the help!
 3 years ago
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