anonymous
  • anonymous
for this quadratic equation, does a=6,b=-3, and c=-2?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[6x ^{2}-3=-2x\]
anonymous
  • anonymous
no....b=2, c=-3
anonymous
  • anonymous
Or should b or c be positive?

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More answers

anonymous
  • anonymous
once you put everything together on one side, you get: 6x^2+2x-3=0
anonymous
  • anonymous
6x^2+2x-3, a=6 b=2 c=-3
anonymous
  • anonymous
ohh because it has x with it?
anonymous
  • anonymous
exactly :)
anonymous
  • anonymous
think of the generic form of polynomials like that: ax^2+bx+c
anonymous
  • anonymous
thanks! I'm going to try and solve it, would you mind checking it to see if I have the correct answer? :)
anonymous
  • anonymous
yup
anonymous
  • anonymous
\[4+ or - \sqrt{76}\over 12\] not sure if this can be simplified or not
anonymous
  • anonymous
D = 4+72 = 76 > 0 --> 2 real number (-2 +- sqrt(76)) 4
anonymous
  • anonymous
yup ur rite sorry im typo, denominator is 12
anonymous
  • anonymous
that should be a -2, not a 4. remember the formula is [-b +/- sqrt(b^2-4ac)]/2a
anonymous
  • anonymous
ohh ok, it is -2 instead of 4 though?
anonymous
  • anonymous
what is b in this equation? its 2...so-b is -2
anonymous
  • anonymous
in the original equation it is -2..but does it turn to positive 2 when we solve it?
anonymous
  • anonymous
in the original is 2, coz its -b so it's -2
anonymous
  • anonymous
ohhhh right. My mistake. thanks for clarifying!
anonymous
  • anonymous
:)
anonymous
  • anonymous
wait a sec..i tried to submit the answer and it says it's not in simplest form?
anonymous
  • anonymous
76=4x19. You can pull out a 2 there and then factor a 2 from the whole numerator and then you end up with: [-1+/-sqrt19]/6
anonymous
  • anonymous
Thanks!

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