Just would like to make sure my answer for this quadratic expression is correct!

- anonymous

Just would like to make sure my answer for this quadratic expression is correct!

- schrodinger

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- anonymous

\[x ^{2}-8x+16=0\]

- anonymous

(x -4)^2=0
x=4, 4

- anonymous

x=4

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## More answers

- anonymous

and so far I have, \[x=8 + or - \sqrt{64-64}\over 2\] I know the 64s can cancel..but what will my answer look like from here?

- anonymous

there are two solutions for this one 4 and 4

- anonymous

ohh so theres one solution? just 4

- anonymous

no..two

- anonymous

ha, sorry i keep typing after you answer my ?

- anonymous

every quad. has two solutions

- anonymous

could be real or complex

- anonymous

4 is 4 so you would only write it once if you were solving by factoring or quadratic formula

- anonymous

ok. this is an online assignment I have to submit so i'd like to get the formula right. I should just put 4 under the 1 solution?

- anonymous

we use the quadratic formula...when u can't factorize or it is hard to guess...but here 4 and 4 add up to 8 and gives the product 16.

- anonymous

there r two solutions.. 4 and 4

- anonymous

ok thanks.. It just seems strange putting only the 4 in as 2 different answers. They are both real solutions?

- anonymous

is it multiple choice

- anonymous

yes they are both real obviously....but dont forget to write it twice otherwise teacher might think u got only one root..

- anonymous

no, I select whether there are 2 different real solutions, 2 non real solutions or 1 solution

- anonymous

ok then ...all good

- anonymous

fan me if u liked my help..thanx

- anonymous

2 real solutions

- anonymous

did you enter it in

- anonymous

It's online so it's picky with the format. Do I have this in a root?

- anonymous

no i haven't yet. I will in a sec

- anonymous

it says two DIFFERENT solutions, I still think it is one solution even if is a quad bc 4 is distinct

- anonymous

i just realized it says one repeated real solution..so maybe i should put it under that category?

- anonymous

I think so to, i'll find out!

- anonymous

yes......

- anonymous

YES!!!!!

- anonymous

yep, that was correct. Sorry, my fault I didn't specify that. Thanks for your help guys!

- anonymous

I knew something wasn't right...you're welcome...fan me please

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