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anonymous
 5 years ago
Find the critical numbers of the function.
h(t) = t^3/4 − 3t^1/4
anonymous
 5 years ago
Find the critical numbers of the function. h(t) = t^3/4 − 3t^1/4

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What did you get for the derivative?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I no im supposed to find the derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and solve for 0, but i didnt no how to solve for 0 for this equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got 3/4t^1/43/4t^3/4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Looks right. Now set that = 0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i did that but because of the exponenti get confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{3}{4t^{1/4}}  \frac{3}{4t^{3/4}} = 0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i factor out 3/4t^1/4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I wouln't bother. Just set \(t^{1/4} = t^{3/4}\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Cause that's the only way those two things can be equal.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{3}{4}t^{1/4}  \frac{3}{4}t^{3/4} = 0\] \[\frac{3}{4}(t^{1/4}  t^{3/4}) = 0\] \[t^{1/4}  t^{3/4} = 0\] \[t^{1/4} = t^{3/4}\] \[t^{1} = t^{3}\] \[\implies t=1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did u get t^1=t^3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0raised both sides to the 4 power.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ooooo so it get crossed out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0omg this way is much simpler then the way my teacher explained it!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But really you coulda guessed t would be 1 looking at the original equation for the derivative because \[\frac{3}{4t^a}  \frac{3}{4t^{3a}} = 0\] Will only be true if \(t^a = t^{3a}\) which means that t must be 1.
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