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anonymous

  • 5 years ago

Could anyone please help me finding the general solution of an ODE? Thanks!! (xy'-1) lnx = 2y

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  1. anonymous
    • 5 years ago
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    rearranging the equation we get, xy' -2y/lnx =1

  2. anonymous
    • 5 years ago
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    integrating facor= 1/ (lnx)^2

  3. anonymous
    • 5 years ago
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    solution will be y *I.F. = INEGRATION SIGN ( I.F.) DX +c

  4. anonymous
    • 5 years ago
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    ok?

  5. anonymous
    • 5 years ago
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    1 sec please

  6. anonymous
    • 5 years ago
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    Yeah thanks a lot ankur 504! I just got it following your rearrangement!!!! Thanks

  7. anonymous
    • 5 years ago
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    best of luck with ur maths

  8. anonymous
    • 5 years ago
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    Could someone tell me the steps of solving this system of differential equations? Thanks!!! x'= x-y+z y'= x+y-z z'= 2x-y

  9. anonymous
    • 5 years ago
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    is it a partial differential problem?

  10. anonymous
    • 5 years ago
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    i am not sure but the hint says that one of the eigenvalues of the correcsponding matrix is r1=1.

  11. anonymous
    • 5 years ago
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    right hand side makes a 3 X 3 matrix.

  12. anonymous
    • 5 years ago
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    yes

  13. anonymous
    • 5 years ago
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    1 -1 1 1 1 -1 2 -1 0

  14. anonymous
    • 5 years ago
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    exactly!!!

  15. anonymous
    • 5 years ago
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    what are the steps then? I can figure the rest by myself if you don't mind giving me some directions.

  16. anonymous
    • 5 years ago
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    ok wait a min..

  17. anonymous
    • 5 years ago
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    we calculate the Jacobian?

  18. anonymous
    • 5 years ago
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    I gave up...I'm just a first year uni student. Sry...U better post your question on the left side...I think POLPAK can solve it

  19. anonymous
    • 5 years ago
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    wow that's pretty impressive. Thanks a lot though!!

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