anonymous
  • anonymous
Could anyone please help me finding the general solution of an ODE? Thanks!! (xy'-1) lnx = 2y
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
rearranging the equation we get, xy' -2y/lnx =1
anonymous
  • anonymous
integrating facor= 1/ (lnx)^2
anonymous
  • anonymous
solution will be y *I.F. = INEGRATION SIGN ( I.F.) DX +c

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anonymous
  • anonymous
ok?
anonymous
  • anonymous
1 sec please
anonymous
  • anonymous
Yeah thanks a lot ankur 504! I just got it following your rearrangement!!!! Thanks
anonymous
  • anonymous
best of luck with ur maths
anonymous
  • anonymous
Could someone tell me the steps of solving this system of differential equations? Thanks!!! x'= x-y+z y'= x+y-z z'= 2x-y
anonymous
  • anonymous
is it a partial differential problem?
anonymous
  • anonymous
i am not sure but the hint says that one of the eigenvalues of the correcsponding matrix is r1=1.
anonymous
  • anonymous
right hand side makes a 3 X 3 matrix.
anonymous
  • anonymous
yes
anonymous
  • anonymous
1 -1 1 1 1 -1 2 -1 0
anonymous
  • anonymous
exactly!!!
anonymous
  • anonymous
what are the steps then? I can figure the rest by myself if you don't mind giving me some directions.
anonymous
  • anonymous
ok wait a min..
anonymous
  • anonymous
we calculate the Jacobian?
anonymous
  • anonymous
I gave up...I'm just a first year uni student. Sry...U better post your question on the left side...I think POLPAK can solve it
anonymous
  • anonymous
wow that's pretty impressive. Thanks a lot though!!

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