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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which one do you want to tackle first?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, what do you know about the length of AD?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer is d, How I can find the length?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What can you tell me about the length of AD by looking at the picture?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the question is what the measure of AD?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes I know. I'm asking what you think about the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you see the picture?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is math. Some thinking is required ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes I can see it. I'm asking what does it tell you? I know what it's telling me.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0given the lenghth AB, BC, CD, I don't get what you asking

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I wonder do you know how to get answer find length AD

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know how to get the answer yes. I want to know what you know? That way I can see how to help you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Nobody cares if I can do it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if given radius is may easy for my to do

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I been thinking many hours but I can't solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Good! You know how to solve it with the radius?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, I can do if I know radius or given tangents or secants

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, well for this we don't actually need the radius. This is called a tangential quadrilateral. It has the property that the two opposite sides will add to the same length.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What do you think about 38?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0w is the weight the total weight have to be less or equal

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0r no more than 12 comes from what statement?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If I tell you, there are 4 reams of paper in the box, what is the weight w?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the given r is the box can carry no more than 12 reams of paper

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so my r is less than 12 it's 4, what is w?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if the box itself weighs 1.3 and each ream weighs 4.4 and there are 4 reams, what is the total weight?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You sure the weight isn't 1 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think 18.9 was correct actually.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But wait, why isn't the weight just 3.1 or 1.3 or 10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Aren't all those < 1.3 + 4.4r ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right. So if I tell you that r=1, what is the weight? It's 1.1111111111111 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because 1.111111 < 1.3 + 4.4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sure, and 1.1111 is less than 5.7, so 1.1111 is the weight? But 0.1274 is also less than 5.7, so which one is the weight?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or is the weight both 1.1111 and 0.1274 or maybe the weight is \(\pi\). I do like \(\pi\). (Here is where you tell me I'm being dumb and the weight is 5.7)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\(\pi\) is less than 5.7 so I think \(\pi\) is the weight. Cause you said anything less than 1.3 + 4.4r was a solution for the weight of a box.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and I said there was 1 ream, so the box can weigh anything less than 5.7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And you say "No dummy the box weighs 5.7"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, thank you so much

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wait. What? Did you find the solution?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes I think w<1.3 + 4.4 r , r<12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no.. that's what I'm trying to explain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Once we pick an r, we know exactly how much the box weighs. The restriction is on r not on the weight.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0w is not any number less than 1.3 + 4.4r. If I tell you r =1, w is not any number less than 5.7. It is 5.7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hrm? I didn't follow that. The answer is G.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If we have r, we know exactly what w is. Not that it's less than something, we know exactly. The only restriction we have is that r must be less than or equal to 12. But will be exactly 1.3 + 4.4r for any r you pick that is allowed.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0err w will be exactly 1.3 + 4.4r

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok , you said w = 1.3+4.4r ,r<12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes. Because once you pick how many reams in the box, the box has an exact wieght.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you pick 1 ream goes in the box, the box will wiegh 5.7. It will not weigh 1.1 or 0.213. If w < 5.7 were the definition then w could be any of those.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It late I go to the bed now bye
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