## anonymous 5 years ago http://img862.imageshack.us/i/page596.jpg/ I need help # 37,38

1. anonymous

Which one do you want to tackle first?

2. anonymous

37 first

3. anonymous

Ok, what do you know about the length of AD?

4. anonymous

the answer is d, How I can find the length?

5. anonymous

What can you tell me about the length of AD by looking at the picture?

6. anonymous

the question is what the measure of AD?

7. anonymous

Yes I know. I'm asking what you think about the problem

8. anonymous

can you see the picture?

9. anonymous

This is math. Some thinking is required ;)

10. anonymous

Yes I can see it. I'm asking what does it tell you? I know what it's telling me.

11. anonymous

yes it math

12. anonymous

given the lenghth AB, BC, CD, I don't get what you asking

13. anonymous

I wonder do you know how to get answer find length AD

14. anonymous

I know how to get the answer yes. I want to know what you know? That way I can see how to help you.

15. anonymous

Nobody cares if I can do it.

16. anonymous

I don't know

17. anonymous

if given radius is may easy for my to do

18. anonymous

I been thinking many hours but I can't solve

19. anonymous

if you can help me ,

20. anonymous

Good! You know how to solve it with the radius?

21. anonymous

yes, I can do if I know radius or given tangents or secants

22. anonymous

Ok, well for this we don't actually need the radius. This is called a tangential quadrilateral. It has the property that the two opposite sides will add to the same length.

23. anonymous

what side?

24. anonymous

AB + CD = AD + BC

25. anonymous

great, thank

26. anonymous

What do you think about 38?

27. anonymous

let me think

28. anonymous

I think H

29. anonymous

Why?

30. anonymous

w is the weight the total weight have to be less or equal

31. anonymous

r no more than 12

32. anonymous

r no more than 12 comes from what statement?

33. anonymous

If I tell you, there are 4 reams of paper in the box, what is the weight w?

34. anonymous

the given r is the box can carry no more than 12 reams of paper

35. anonymous

right.

36. anonymous

so my r is less than 12 it's 4, what is w?

37. anonymous

4.4

38. anonymous

if the box itself weighs 1.3 and each ream weighs 4.4 and there are 4 reams, what is the total weight?

39. anonymous

total; 18.9 w

40. anonymous

You sure the weight isn't 1 ?

41. anonymous

22.8w

42. anonymous

I think 18.9 was correct actually.

43. anonymous

But wait, why isn't the weight just 3.1 or 1.3 or 10

44. anonymous

Aren't all those < 1.3 + 4.4r ?

45. anonymous

w<1.3 +4.4r, r<12

46. anonymous

Right. So if I tell you that r=1, what is the weight? It's 1.1111111111111 right?

47. anonymous

because 1.111111 < 1.3 + 4.4

48. anonymous

r=1? w<5.7

49. anonymous

Sure, and 1.1111 is less than 5.7, so 1.1111 is the weight? But 0.1274 is also less than 5.7, so which one is the weight?

50. anonymous

Or is the weight both 1.1111 and 0.1274 or maybe the weight is $$\pi$$. I do like $$\pi$$. (Here is where you tell me I'm being dumb and the weight is 5.7)

51. anonymous

$$\pi$$ is less than 5.7 so I think $$\pi$$ is the weight. Cause you said anything less than 1.3 + 4.4r was a solution for the weight of a box.

52. anonymous

and I said there was 1 ream, so the box can weigh anything less than 5.7

53. anonymous

And you say "No dummy the box weighs 5.7"

54. anonymous

;)

55. anonymous

ok, thank you so much

56. anonymous

Wait. What? Did you find the solution?

57. anonymous

yes I think w<1.3 + 4.4 r , r<12

58. anonymous

no.. that's what I'm trying to explain

59. anonymous

Once we pick an r, we know exactly how much the box weighs. The restriction is on r not on the weight.

60. anonymous

w is not any number less than 1.3 + 4.4r. If I tell you r =1, w is not any number less than 5.7. It is 5.7

61. anonymous

the key not reqite r

62. anonymous

hrm? I didn't follow that. The answer is G.

63. anonymous

If we have r, we know exactly what w is. Not that it's less than something, we know exactly. The only restriction we have is that r must be less than or equal to 12. But will be exactly 1.3 + 4.4r for any r you pick that is allowed.

64. anonymous

err w will be exactly 1.3 + 4.4r

65. anonymous

Ok , you said w = 1.3+4.4r ,r<12

66. anonymous

yes. Because once you pick how many reams in the box, the box has an exact wieght.

67. anonymous

if you pick 1 ream goes in the box, the box will wiegh 5.7. It will not weigh 1.1 or 0.213. If w < 5.7 were the definition then w could be any of those.

68. anonymous

OK, it help

69. anonymous

I understand now

70. anonymous

thank you

71. anonymous

no problem

72. anonymous

It late I go to the bed now bye