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anonymous
 5 years ago
How do you find the limit as x goes to infinity of 5^1/x divide by 3/x
anonymous
 5 years ago
How do you find the limit as x goes to infinity of 5^1/x divide by 3/x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just to clarify, this is \[\lim_{x \rightarrow \infty}5^{1/x}/(3/x)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if that's correct... then you can imagine you're plugging in "infinity" for where x is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 5^(1/INF) becomes 5^0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am gonna assume, it's like holy43 postet. You just have to think about what happens to the term 5^(1/x) when you plug in a really, really big number for x... ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0damnit  you were too fast  but yeah  that's correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then the denominator will become a super small number. (approaches 0...)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and then think about what happens when you have anything over an infinitely small number

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a way you can test is to try and do (1/0.1) then (1/0.01) then (1/0.001) then even (1/0.000001). and you can look at the behavior of how the number changes each time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or if you invert the denominator and multiply, you'll have x on top, which will get really really huge :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0therefore answer = \[\infty\]
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