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anonymous

  • 5 years ago

hi this is a question on using the chain rule for partial differential equations. converting from U(x,y) to U(v,w) given Ux= Uv.Vx + Uw.Wx What is Uxy?

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  1. anonymous
    • 5 years ago
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    Is this how the question is asked; i have never seen a question worded like this.

  2. anonymous
    • 5 years ago
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    no the actual question is just to convert from U(x,y) to U(v,w) and I need to find Uxx, Uxy and Uyy in terms of v and w probably need to use the chain rule but i'm not sure how to apply it

  3. anonymous
    • 5 years ago
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    Please write out the question exactly as it was given to you.

  4. anonymous
    • 5 years ago
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    Transform to the normal and solve: Uxx - 4Uxy + 4Uyy = 0

  5. anonymous
    • 5 years ago
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    It is difficult to help you because your posts are incomplete. The post you just sent is totally different from the others. In addition the post is not complete. It tells you solve but solve for what? In addition the question usually gives you a set of conditions, saying something like xy is a factor of U and V etc.

  6. anonymous
    • 5 years ago
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    I'm sorry about the incomplete posts. Its just that I just started partial differential equations and I have no idea what is going on. These are the two conditions: v=x w=y+2x Does that help?

  7. anonymous
    • 5 years ago
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    The subject matter is new but just post the whole question as it was given to you. You are interpreting the question and at the same time you admit you don't know what is going on. May be start a new post and post the whole question as it reads from the book or your homework assignment.

  8. anonymous
    • 5 years ago
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    yeah lol post the whole question... you are missing info

  9. anonymous
    • 5 years ago
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    This is the question, and the solution that came with it. But I dont understand how they got there. I'm really confused as to how they got the equations for Uxx Uxy and Uyy

  10. anonymous
    • 5 years ago
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    No wonder you are confused. I am equally confused. I thought you were doing partial differentiations which is real simple but you took it up another notch to partial differential equations. Just start a new post and maybe someone will pick it up.

  11. anonymous
    • 5 years ago
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    yeah lol partial differentials are no problem for me. But this i have no clue. Thanks a lot though

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